What is the general solution for sin(t)= 7/9 ,sin(2t) ?

The general solution for sin(t)= 7/9 ,sin(2t) is No Solution for t\in\mathbb{R}

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sin(t)= 7/9 ,sin(2t)

sin (t) = \frac{7}{9}, sin (2 t)

No Solution for t \in R

Solution steps

sin (t) = \frac{7}{9}, sin (2 t)

Apply trig inverse properties

sin (t) = \frac{7}{9}

General solutions for

sin (t) = \frac{7}{9}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

t = arcsin (\frac{7}{9}) + 2 πn, t = π - arcsin (\frac{7}{9}) + 2 πn

t = arcsin (\frac{7}{9}) + 2 πn, t = π - arcsin (\frac{7}{9}) + 2 πn

Solutions for the range

sin (2 t)

No Solution for t \in R

\frac{8}{17} = sin (2 x)

sec (2 x) + tan (2 x) = 2

sec (2 x) + tan (2 x) = 9

2 + 3 cos^{2} (x) = sin^{2} (x) + 4 cos (x)

sin (x) - 3 cos (x) = 0

What is the general solution for sin(t)= 7/9 ,sin(2t) ?
The general solution for sin(t)= 7/9 ,sin(2t) is No Solution for t\in\mathbb{R}