What is the general solution for 2sin^2(x/3)=1,-pi<= ,x<= pi ?

Q: What is the general solution for 2sin^2(x/3)=1,-pi<= ,x<= pi ?

The general solution for 2sin^2(x/3)=1,-pi<= ,x<= pi is No Solution for x\in\mathbb{R}

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2sin^2(x/3)=1,-pi<= ,x<= pi

Solution

2 sin^{2} (\frac{x}{3}) = 1, - π \leq, x \leq π

Solution

No Solution for x \in R

Solution steps

2 sin^{2} (\frac{x}{3}) = 1, - π, x \leq π

Solve by substitution

2 sin^{2} (\frac{x}{3}) = 1

Let:

sin (\frac{x}{3}) = u

2 u^{2} = 1

2 u^{2} = 1 : u = \frac{1}{2}, u = - \frac{1}{2}

2 u^{2} = 1

Divide both sides by

2

2 u^{2} = 1

Divide both sides by

2

\frac{2 u ^{2}}{2} = \frac{1}{2}

Simplify

u^{2} = \frac{1}{2}

u^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = \frac{1}{2}, u = - \frac{1}{2}

Substitute back

u = sin (\frac{x}{3})

sin (\frac{x}{3}) = \frac{1}{2}, sin (\frac{x}{3}) = - \frac{1}{2}

sin (\frac{x}{3}) = \frac{1}{2}, sin (\frac{x}{3}) = - \frac{1}{2}

sin (\frac{x}{3}) = \frac{1}{2}, - π :

No Solution

sin (\frac{x}{3}) = \frac{1}{2}, - π

General solutions for

sin (\frac{x}{3}) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

\frac{x}{3} = \frac{π}{4} + 2 πn, \frac{x}{3} = \frac{3 π}{4} + 2 πn

\frac{x}{3} = \frac{π}{4} + 2 πn, \frac{x}{3} = \frac{3 π}{4} + 2 πn

Solve

\frac{x}{3} = \frac{π}{4} + 2 πn : x = \frac{3 π}{4} + 6 πn

\frac{x}{3} = \frac{π}{4} + 2 πn

Multiply both sides by

3

\frac{x}{3} = \frac{π}{4} + 2 πn

Multiply both sides by

3

\frac{3 x}{3} = 3 \cdot \frac{π}{4} + 3 \cdot 2 πn

Simplify

\frac{3 x}{3} = 3 \cdot \frac{π}{4} + 3 \cdot 2 πn

Simplify

\frac{3 x}{3} : x

\frac{3 x}{3}

Divide the numbers:

\frac{3}{3} = 1

= x

Simplify

3 \cdot \frac{π}{4} + 3 \cdot 2 πn : \frac{3 π}{4} + 6 πn

3 \cdot \frac{π}{4} + 3 \cdot 2 πn

Multiply

3 \cdot \frac{π}{4} : \frac{3 π}{4}

3 \cdot \frac{π}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 3}{4}

= \frac{3 π}{4} + 3 \cdot 2 πn

Multiply the numbers:

3 \cdot 2 = 6

= \frac{3 π}{4} + 6 πn

x = \frac{3 π}{4} + 6 πn

x = \frac{3 π}{4} + 6 πn

x = \frac{3 π}{4} + 6 πn

Solve

\frac{x}{3} = \frac{3 π}{4} + 2 πn : x = \frac{9 π}{4} + 6 πn

\frac{x}{3} = \frac{3 π}{4} + 2 πn

Multiply both sides by

3

\frac{x}{3} = \frac{3 π}{4} + 2 πn

Multiply both sides by

3

\frac{3 x}{3} = 3 \cdot \frac{3 π}{4} + 3 \cdot 2 πn

Simplify

\frac{3 x}{3} = 3 \cdot \frac{3 π}{4} + 3 \cdot 2 πn

Simplify

\frac{3 x}{3} : x

\frac{3 x}{3}

Divide the numbers:

\frac{3}{3} = 1

= x

Simplify

3 \cdot \frac{3 π}{4} + 3 \cdot 2 πn : \frac{9 π}{4} + 6 πn

3 \cdot \frac{3 π}{4} + 3 \cdot 2 πn

3 \cdot \frac{3 π}{4} = \frac{9 π}{4}

3 \cdot \frac{3 π}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 π 3}{4}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{9 π}{4}

3 \cdot 2 πn = 6 πn

3 \cdot 2 πn

Multiply the numbers:

3 \cdot 2 = 6

= 6 πn

= \frac{9 π}{4} + 6 πn

x = \frac{9 π}{4} + 6 πn

x = \frac{9 π}{4} + 6 πn

x = \frac{9 π}{4} + 6 πn

x = \frac{3 π}{4} + 6 πn, x = \frac{9 π}{4} + 6 πn

Solutions for the range

- π

No Solution

sin (\frac{x}{3}) = - \frac{1}{2}, - π :

No Solution

sin (\frac{x}{3}) = - \frac{1}{2}, - π

General solutions for

sin (\frac{x}{3}) = - \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

\frac{x}{3} = \frac{5 π}{4} + 2 πn, \frac{x}{3} = \frac{7 π}{4} + 2 πn

\frac{x}{3} = \frac{5 π}{4} + 2 πn, \frac{x}{3} = \frac{7 π}{4} + 2 πn

Solve

\frac{x}{3} = \frac{5 π}{4} + 2 πn : x = \frac{15 π}{4} + 6 πn

\frac{x}{3} = \frac{5 π}{4} + 2 πn

Multiply both sides by

3

\frac{x}{3} = \frac{5 π}{4} + 2 πn

Multiply both sides by

3

\frac{3 x}{3} = 3 \cdot \frac{5 π}{4} + 3 \cdot 2 πn

Simplify

\frac{3 x}{3} = 3 \cdot \frac{5 π}{4} + 3 \cdot 2 πn

Simplify

\frac{3 x}{3} : x

\frac{3 x}{3}

Divide the numbers:

\frac{3}{3} = 1

= x

Simplify

3 \cdot \frac{5 π}{4} + 3 \cdot 2 πn : \frac{15 π}{4} + 6 πn

3 \cdot \frac{5 π}{4} + 3 \cdot 2 πn

3 \cdot \frac{5 π}{4} = \frac{15 π}{4}

3 \cdot \frac{5 π}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{5 π 3}{4}

Multiply the numbers:

5 \cdot 3 = 15

= \frac{15 π}{4}

3 \cdot 2 πn = 6 πn

3 \cdot 2 πn

Multiply the numbers:

3 \cdot 2 = 6

= 6 πn

= \frac{15 π}{4} + 6 πn

x = \frac{15 π}{4} + 6 πn

x = \frac{15 π}{4} + 6 πn

x = \frac{15 π}{4} + 6 πn

Solve

\frac{x}{3} = \frac{7 π}{4} + 2 πn : x = \frac{21 π}{4} + 6 πn

\frac{x}{3} = \frac{7 π}{4} + 2 πn

Multiply both sides by

3

\frac{x}{3} = \frac{7 π}{4} + 2 πn

Multiply both sides by

3

\frac{3 x}{3} = 3 \cdot \frac{7 π}{4} + 3 \cdot 2 πn

Simplify

\frac{3 x}{3} = 3 \cdot \frac{7 π}{4} + 3 \cdot 2 πn

Simplify

\frac{3 x}{3} : x

\frac{3 x}{3}

Divide the numbers:

\frac{3}{3} = 1

= x

Simplify

3 \cdot \frac{7 π}{4} + 3 \cdot 2 πn : \frac{21 π}{4} + 6 πn

3 \cdot \frac{7 π}{4} + 3 \cdot 2 πn

3 \cdot \frac{7 π}{4} = \frac{21 π}{4}

3 \cdot \frac{7 π}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{7 π 3}{4}

Multiply the numbers:

7 \cdot 3 = 21

= \frac{21 π}{4}

3 \cdot 2 πn = 6 πn

3 \cdot 2 πn

Multiply the numbers:

3 \cdot 2 = 6

= 6 πn

= \frac{21 π}{4} + 6 πn

x = \frac{21 π}{4} + 6 πn

x = \frac{21 π}{4} + 6 πn

x = \frac{21 π}{4} + 6 πn

x = \frac{15 π}{4} + 6 πn, x = \frac{21 π}{4} + 6 πn

Solutions for the range

- π

No Solution

Combine all the solutions

No Solution for x \in R

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Frequently Asked Questions (FAQ)

What is the general solution for 2sin^2(x/3)=1,-pi<= ,x<= pi ?
The general solution for 2sin^2(x/3)=1,-pi<= ,x<= pi is No Solution for x\in\mathbb{R}