What is the general solution for solvefor t,y=cos(t) ?

The general solution for solvefor t,y=cos(t) is t=arccos(y)+2pin,t=-arccos(y)+2pin

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solvefor t,y=cos(t)

solve for

t, y = cos (t)

t = arccos (y) + 2 πn, t = - arccos (y) + 2 πn

Solution steps

y = cos (t)

Switch sides

cos (t) = y

Apply trig inverse properties

cos (t) = y

General solutions for

cos (t) = y

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

t = arccos (y) + 2 πn, t = - arccos (y) + 2 πn

t = arccos (y) + 2 πn, t = - arccos (y) + 2 πn

x, r^{2} = 9 cos (2 x)

csc (a) = \frac{13}{12}

(cos (θ) + 1) (tan (θ) + 1) = 0

(tan^{2} (3 x)) (csc (3 x)) + 1 = - 1 \cdot sec^{2} (3 x)

\frac{4 sin ( x ) - 3 cos ( x )}{3 sin ( x ) + 4 cos ( x )} = 3

What is the general solution for solvefor t,y=cos(t) ?
The general solution for solvefor t,y=cos(t) is t=arccos(y)+2pin,t=-arccos(y)+2pin