en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,r^2=9cos(2x)

Solution

solve for

x, r^{2} = 9 cos (2 x)

Solution

x = \frac{arccos ( \frac{r ^{2}}{9} )}{2} + πn, x = - \frac{arccos ( \frac{r ^{2}}{9} )}{2} + πn

Solution steps

r^{2} = 9 cos (2 x)

Switch sides

9 cos (2 x) = r^{2}

Divide both sides by

9

9 cos (2 x) = r^{2}

Divide both sides by

9

\frac{9 cos ( 2 x )}{9} = \frac{r ^{2}}{9}

Simplify

cos (2 x) = \frac{r ^{2}}{9}

cos (2 x) = \frac{r ^{2}}{9}

Apply trig inverse properties

cos (2 x) = \frac{r ^{2}}{9}

General solutions for

cos (2 x) = \frac{r ^{2}}{9}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

2 x = arccos (\frac{r ^{2}}{9}) + 2 πn, 2 x = - arccos (\frac{r ^{2}}{9}) + 2 πn

2 x = arccos (\frac{r ^{2}}{9}) + 2 πn, 2 x = - arccos (\frac{r ^{2}}{9}) + 2 πn

Solve

2 x = arccos (\frac{r ^{2}}{9}) + 2 πn : x = \frac{arccos ( \frac{r ^{2}}{9} )}{2} + πn

2 x = arccos (\frac{r ^{2}}{9}) + 2 πn

Divide both sides by

2

2 x = arccos (\frac{r ^{2}}{9}) + 2 πn

Divide both sides by

2

\frac{2 x}{2} = \frac{arccos ( \frac{r ^{2}}{9} )}{2} + \frac{2 πn}{2}

Simplify

x = \frac{arccos ( \frac{r ^{2}}{9} )}{2} + πn

x = \frac{arccos ( \frac{r ^{2}}{9} )}{2} + πn

Solve

2 x = - arccos (\frac{r ^{2}}{9}) + 2 πn : x = - \frac{arccos ( \frac{r ^{2}}{9} )}{2} + πn

2 x = - arccos (\frac{r ^{2}}{9}) + 2 πn

Divide both sides by

2

2 x = - arccos (\frac{r ^{2}}{9}) + 2 πn

Divide both sides by

2

\frac{2 x}{2} = - \frac{arccos ( \frac{r ^{2}}{9} )}{2} + \frac{2 πn}{2}

Simplify

x = - \frac{arccos ( \frac{r ^{2}}{9} )}{2} + πn

x = - \frac{arccos ( \frac{r ^{2}}{9} )}{2} + πn

x = \frac{arccos ( \frac{r ^{2}}{9} )}{2} + πn, x = - \frac{arccos ( \frac{r ^{2}}{9} )}{2} + πn

Popular Examples

csc (a) = \frac{13}{12}

(cos(θ)+1)(tan(θ)+1)=0

(cos (θ) + 1) (tan (θ) + 1) = 0

(tan^2(3x))(csc(3x))+1=-1*sec^2(3x)

(tan^{2} (3 x)) (csc (3 x)) + 1 = - 1 \cdot sec^{2} (3 x)

(4sin(x)-3cos(x))/(3sin(x)+4cos(x))=3

\frac{4 sin ( x ) - 3 cos ( x )}{3 sin ( x ) + 4 cos ( x )} = 3

7=10sin(40(0-h))+17

7 = 10 sin (40 (0 - h)) + 17