What is the general solution for sin(x+2)=cos(x-2) ?

The general solution for sin(x+2)=cos(x-2) is x=-360n+45,x=-135-360n

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Popular Trigonometry >

sin(x+2)=cos(x-2)

Solution

sin (x + 2^{\circ}) = cos (x - 2^{\circ})

Solution

x = - 36 0^{\circ} n + 4 5^{\circ}, x = - 13 5^{\circ} - 36 0^{\circ} n

Radians

x = \frac{π}{4} - 2 πn, x = - \frac{3 π}{4} - 2 πn

Solution steps

sin (x + 2^{\circ}) = cos (x - 2^{\circ})

Subtract

cos (x - 2^{\circ})

from both sides

sin (x + 2^{\circ}) - cos (x - 2^{\circ}) = 0

Simplify

sin (x + 2^{\circ}) - cos (x - 2^{\circ}) : sin (\frac{90 x + 18 0 ^{\circ}}{90}) - cos (\frac{90 x - 18 0 ^{\circ}}{90})

sin (x + 2^{\circ}) - cos (x - 2^{\circ})

Join

x + 2^{\circ} : \frac{90 x + 18 0 ^{\circ}}{90}

x + 2^{\circ}

Convert element to fraction:

x = \frac{x 90}{90}

= \frac{x \cdot 90}{90} + 2^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{x \cdot 90 + 18 0 ^{\circ}}{90}

= sin (\frac{90 x + 18 0 ^{\circ}}{90}) - cos (x - 2^{\circ})

Join

x - 2^{\circ} : \frac{90 x - 18 0 ^{\circ}}{90}

x - 2^{\circ}

Convert element to fraction:

x = \frac{x 90}{90}

= \frac{x \cdot 90}{90} - 2^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{x \cdot 90 - 18 0 ^{\circ}}{90}

= sin (\frac{90 x + 18 0 ^{\circ}}{90}) - cos (\frac{90 x - 18 0 ^{\circ}}{90})

sin (\frac{90 x + 18 0 ^{\circ}}{90}) - cos (\frac{90 x - 18 0 ^{\circ}}{90}) = 0

Rewrite using trig identities

- cos (\frac{- 18 0 ^{\circ} + 90 x}{90}) + sin (\frac{18 0 ^{\circ} + 90 x}{90})

Use the following identity:

sin (x) = cos (9 0^{\circ} - x)

= - cos (\frac{- 18 0 ^{\circ} + 90 x}{90}) + cos (9 0^{\circ} - \frac{18 0 ^{\circ} + 90 x}{90})

Join

9 0^{\circ} - \frac{18 0 ^{\circ} + 90 x}{90} : \frac{396 0 ^{\circ} - 45 x}{45}

9 0^{\circ} - \frac{18 0 ^{\circ} + 90 x}{90}

Least Common Multiplier of

2, 90 : 90

2, 90

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

90 : 2 \cdot 3 \cdot 3 \cdot 5

90

90

divides by

290 = 45 \cdot 2

= 2 \cdot 45

45

divides by

345 = 15 \cdot 3

= 2 \cdot 3 \cdot 15

15

divides by

315 = 5 \cdot 3

= 2 \cdot 3 \cdot 3 \cdot 5

2, 3, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3 \cdot 3 \cdot 5

Multiply each factor the greatest number of times it occurs in either

2

90

= 2 \cdot 3 \cdot 3 \cdot 5

Multiply the numbers:

2 \cdot 3 \cdot 3 \cdot 5 = 90

= 90

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

90

For

9 0^{\circ} :

multiply the denominator and numerator by

45

9 0^{\circ} = \frac{18 0 ^{\circ} 45}{2 \cdot 45} = 9 0^{\circ}

= 9 0^{\circ} - \frac{18 0 ^{\circ} + 90 x}{90}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} 45 - ( 18 0 ^{\circ} + 90 x )}{90}

Expand

18 0^{\circ} 45 - (18 0^{\circ} + 90 x) : 792 0^{\circ} - 90 x

18 0^{\circ} 45 - (18 0^{\circ} + 90 x)

= 810 0^{\circ} - (18 0^{\circ} + 90 x)

- (18 0^{\circ} + 90 x) : - 18 0^{\circ} - 90 x

- (18 0^{\circ} + 90 x)

Distribute parentheses

= - (18 0^{\circ}) - (90 x)

Apply minus-plus rules

+ (- a) = - a

= - 18 0^{\circ} - 90 x

= 18 0^{\circ} 45 - 18 0^{\circ} - 90 x

Add similar elements:

810 0^{\circ} - 18 0^{\circ} = 792 0^{\circ}

= 792 0^{\circ} - 90 x

= \frac{792 0 ^{\circ} - 90 x}{90}

Factor

792 0^{\circ} - 90 x : 2 (396 0^{\circ} - 45 x)

792 0^{\circ} - 90 x

Rewrite as

= 2 \cdot 396 0^{\circ} - 2 \cdot 45 x

Factor out common term

2

= 2 (396 0^{\circ} - 45 x)

= \frac{2 ( 396 0 ^{\circ} - 45 x )}{90}

Cancel the common factor:

2

= \frac{396 0 ^{\circ} - 45 x}{45}

= - cos (\frac{- 18 0 ^{\circ} + 90 x}{90}) + cos (\frac{396 0 ^{\circ} - 45 x}{45})

Use the Sum to Product identity:

cos (s) - cos (t) = - 2 sin (\frac{s + t}{2}) sin (\frac{s - t}{2})

= - 2 sin (\frac{\frac{396 0 ^{\circ} - 45 x}{45} + \frac{- 18 0 ^{\circ} + 90 x}{90}}{2}) sin (\frac{\frac{396 0 ^{\circ} - 45 x}{45} - \frac{- 18 0 ^{\circ} + 90 x}{90}}{2})

Simplify

- 2 sin (\frac{\frac{396 0 ^{\circ} - 45 x}{45} + \frac{- 18 0 ^{\circ} + 90 x}{90}}{2}) sin (\frac{\frac{396 0 ^{\circ} - 45 x}{45} - \frac{- 18 0 ^{\circ} + 90 x}{90}}{2}) : - 2 sin (4 3^{\circ}) sin (\frac{- 4 x + 18 0 ^{\circ}}{4})

- 2 sin (\frac{\frac{396 0 ^{\circ} - 45 x}{45} + \frac{- 18 0 ^{\circ} + 90 x}{90}}{2}) sin (\frac{\frac{396 0 ^{\circ} - 45 x}{45} - \frac{- 18 0 ^{\circ} + 90 x}{90}}{2})

\frac{\frac{396 0 ^{\circ} - 45 x}{45} + \frac{- 18 0 ^{\circ} + 90 x}{90}}{2} = 4 3^{\circ}

\frac{\frac{396 0 ^{\circ} - 45 x}{45} + \frac{- 18 0 ^{\circ} + 90 x}{90}}{2}

Join

\frac{396 0 ^{\circ} - 45 x}{45} + \frac{- 18 0 ^{\circ} + 90 x}{90} : 8 6^{\circ}

\frac{396 0 ^{\circ} - 45 x}{45} + \frac{- 18 0 ^{\circ} + 90 x}{90}

Least Common Multiplier of

45, 90 : 90

45, 90

Least Common Multiplier (LCM)

Prime factorization of

45 : 3 \cdot 3 \cdot 5

45

45

divides by

345 = 15 \cdot 3

= 3 \cdot 15

15

divides by

315 = 5 \cdot 3

= 3 \cdot 3 \cdot 5

3, 5

are all prime numbers, therefore no further factorization is possible

= 3 \cdot 3 \cdot 5

Prime factorization of

90 : 2 \cdot 3 \cdot 3 \cdot 5

90

90

divides by

290 = 45 \cdot 2

= 2 \cdot 45

45

divides by

345 = 15 \cdot 3

= 2 \cdot 3 \cdot 15

15

divides by

315 = 5 \cdot 3

= 2 \cdot 3 \cdot 3 \cdot 5

2, 3, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3 \cdot 3 \cdot 5

Multiply each factor the greatest number of times it occurs in either

45

90

= 3 \cdot 3 \cdot 5 \cdot 2

Multiply the numbers:

3 \cdot 3 \cdot 5 \cdot 2 = 90

= 90

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

90

For

\frac{396 0 ^{\circ} - 45 x}{45} :

multiply the denominator and numerator by

2

\frac{396 0 ^{\circ} - 45 x}{45} = \frac{( 396 0 ^{\circ} - 45 x ) \cdot 2}{45 \cdot 2} = \frac{( 396 0 ^{\circ} - 45 x ) \cdot 2}{90}

= \frac{( 396 0 ^{\circ} - 45 x ) \cdot 2}{90} + \frac{- 18 0 ^{\circ} + 90 x}{90}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( 396 0 ^{\circ} - 45 x ) \cdot 2 - 18 0 ^{\circ} + 90 x}{90}

Expand

(396 0^{\circ} - 45 x) \cdot 2 - 18 0^{\circ} + 90 x : 774 0^{\circ}

(396 0^{\circ} - 45 x) \cdot 2 - 18 0^{\circ} + 90 x

= 2 (396 0^{\circ} - 45 x) - 18 0^{\circ} + 90 x

Expand

2 (396 0^{\circ} - 45 x) : 792 0^{\circ} - 90 x

2 (396 0^{\circ} - 45 x)

Apply the distributive law:

a (b - c) = ab - a c

a = 2, b = 396 0^{\circ}, c = 45 x

= 2 \cdot 396 0^{\circ} - 2 \cdot 45 x

Simplify

2 \cdot 396 0^{\circ} - 2 \cdot 45 x : 792 0^{\circ} - 90 x

2 \cdot 396 0^{\circ} - 2 \cdot 45 x

Multiply the numbers:

2 \cdot 22 = 44

= 792 0^{\circ} - 2 \cdot 45 x

Multiply the numbers:

2 \cdot 45 = 90

= 792 0^{\circ} - 90 x

= 792 0^{\circ} - 90 x

= 792 0^{\circ} - 90 x - 18 0^{\circ} + 90 x

Simplify

792 0^{\circ} - 90 x - 18 0^{\circ} + 90 x : 774 0^{\circ}

792 0^{\circ} - 90 x - 18 0^{\circ} + 90 x

Group like terms

= - 90 x + 90 x + 792 0^{\circ} - 18 0^{\circ}

Add similar elements:

- 90 x + 90 x = 0

= 792 0^{\circ} - 18 0^{\circ}

Add similar elements:

792 0^{\circ} - 18 0^{\circ} = 774 0^{\circ}

= 774 0^{\circ}

= 774 0^{\circ}

= 8 6^{\circ}

= \frac{8 6 ^{\circ}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{774 0 ^{\circ}}{90 \cdot 2}

Multiply the numbers:

90 \cdot 2 = 180

= 4 3^{\circ}

= - 2 sin (4 3^{\circ}) sin (\frac{\frac{- 45 x + 396 0 ^{\circ}}{45} - \frac{90 x - 18 0 ^{\circ}}{90}}{2})

\frac{\frac{396 0 ^{\circ} - 45 x}{45} - \frac{- 18 0 ^{\circ} + 90 x}{90}}{2} = \frac{- 4 x + 18 0 ^{\circ}}{4}

\frac{\frac{396 0 ^{\circ} - 45 x}{45} - \frac{- 18 0 ^{\circ} + 90 x}{90}}{2}

Join

\frac{396 0 ^{\circ} - 45 x}{45} - \frac{- 18 0 ^{\circ} + 90 x}{90} : \frac{- 4 x + 18 0 ^{\circ}}{2}

\frac{396 0 ^{\circ} - 45 x}{45} - \frac{- 18 0 ^{\circ} + 90 x}{90}

Least Common Multiplier of

45, 90 : 90

45, 90

Least Common Multiplier (LCM)

Prime factorization of

45 : 3 \cdot 3 \cdot 5

45

45

divides by

345 = 15 \cdot 3

= 3 \cdot 15

15

divides by

315 = 5 \cdot 3

= 3 \cdot 3 \cdot 5

3, 5

are all prime numbers, therefore no further factorization is possible

= 3 \cdot 3 \cdot 5

Prime factorization of

90 : 2 \cdot 3 \cdot 3 \cdot 5

90

90

divides by

290 = 45 \cdot 2

= 2 \cdot 45

45

divides by

345 = 15 \cdot 3

= 2 \cdot 3 \cdot 15

15

divides by

315 = 5 \cdot 3

= 2 \cdot 3 \cdot 3 \cdot 5

2, 3, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3 \cdot 3 \cdot 5

Multiply each factor the greatest number of times it occurs in either

45

90

= 3 \cdot 3 \cdot 5 \cdot 2

Multiply the numbers:

3 \cdot 3 \cdot 5 \cdot 2 = 90

= 90

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

90

For

\frac{396 0 ^{\circ} - 45 x}{45} :

multiply the denominator and numerator by

2

\frac{396 0 ^{\circ} - 45 x}{45} = \frac{( 396 0 ^{\circ} - 45 x ) \cdot 2}{45 \cdot 2} = \frac{( 396 0 ^{\circ} - 45 x ) \cdot 2}{90}

= \frac{( 396 0 ^{\circ} - 45 x ) \cdot 2}{90} - \frac{- 18 0 ^{\circ} + 90 x}{90}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( 396 0 ^{\circ} - 45 x ) \cdot 2 - ( - 18 0 ^{\circ} + 90 x )}{90}

Expand

(396 0^{\circ} - 45 x) \cdot 2 - (- 18 0^{\circ} + 90 x) : - 180 x + 810 0^{\circ}

(396 0^{\circ} - 45 x) \cdot 2 - (- 18 0^{\circ} + 90 x)

= 2 (396 0^{\circ} - 45 x) - (- 18 0^{\circ} + 90 x)

Expand

2 (396 0^{\circ} - 45 x) : 792 0^{\circ} - 90 x

2 (396 0^{\circ} - 45 x)

Apply the distributive law:

a (b - c) = ab - a c

a = 2, b = 396 0^{\circ}, c = 45 x

= 2 \cdot 396 0^{\circ} - 2 \cdot 45 x

Simplify

2 \cdot 396 0^{\circ} - 2 \cdot 45 x : 792 0^{\circ} - 90 x

2 \cdot 396 0^{\circ} - 2 \cdot 45 x

Multiply the numbers:

2 \cdot 22 = 44

= 792 0^{\circ} - 2 \cdot 45 x

Multiply the numbers:

2 \cdot 45 = 90

= 792 0^{\circ} - 90 x

= 792 0^{\circ} - 90 x

= 792 0^{\circ} - 90 x - (- 18 0^{\circ} + 90 x)

- (- 18 0^{\circ} + 90 x) : 18 0^{\circ} - 90 x

- (- 18 0^{\circ} + 90 x)

Distribute parentheses

= - (- 18 0^{\circ}) - (90 x)

Apply minus-plus rules

- (- a) = a, - (a) = - a

= 18 0^{\circ} - 90 x

= 792 0^{\circ} - 90 x + 18 0^{\circ} - 90 x

Simplify

792 0^{\circ} - 90 x + 18 0^{\circ} - 90 x : - 180 x + 810 0^{\circ}

792 0^{\circ} - 90 x + 18 0^{\circ} - 90 x

Group like terms

= - 90 x - 90 x + 792 0^{\circ} + 18 0^{\circ}

Add similar elements:

- 90 x - 90 x = - 180 x

= - 180 x + 792 0^{\circ} + 18 0^{\circ}

Add similar elements:

792 0^{\circ} + 18 0^{\circ} = 810 0^{\circ}

= - 180 x + 810 0^{\circ}

= - 180 x + 810 0^{\circ}

= \frac{- 180 x + 810 0 ^{\circ}}{90}

Factor

- 180 x + 810 0^{\circ} : 45 (- 4 x + 18 0^{\circ})

- 180 x + 810 0^{\circ}

Rewrite as

= - 45 \cdot 4 x + 810 0^{\circ}

Factor out common term

45

= 45 (- 4 x + 18 0^{\circ})

= \frac{45 ( - 4 x + 18 0 ^{\circ} )}{90}

Cancel the common factor:

45

= \frac{- 4 x + 18 0 ^{\circ}}{2}

= \frac{\frac{- 4 x + 18 0 ^{\circ}}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{- 4 x + 18 0 ^{\circ}}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{- 4 x + 18 0 ^{\circ}}{4}

= - 2 sin (4 3^{\circ}) sin (\frac{- 4 x + 18 0 ^{\circ}}{4})

= - 2 sin (4 3^{\circ}) sin (\frac{- 4 x + 18 0 ^{\circ}}{4})

- 2 sin (4 3^{\circ}) sin (\frac{- 4 x + 18 0 ^{\circ}}{4}) = 0

Divide both sides by

- 2 sin (4 3^{\circ})

- 2 sin (4 3^{\circ}) sin (\frac{- 4 x + 18 0 ^{\circ}}{4}) = 0

Divide both sides by

- 2 sin (4 3^{\circ})

\frac{- 2 sin ( 4 3 ^{\circ} ) sin ( \frac{- 4 x + 18 0 ^{\circ}}{4} )}{- 2 sin ( 4 3 ^{\circ} )} = \frac{0}{- 2 sin ( 4 3 ^{\circ} )}

Simplify

sin (\frac{- 4 x + 18 0 ^{\circ}}{4}) = 0

sin (\frac{- 4 x + 18 0 ^{\circ}}{4}) = 0

General solutions for

sin (\frac{- 4 x + 18 0 ^{\circ}}{4}) = 0

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

\frac{- 4 x + 18 0 ^{\circ}}{4} = 0 + 36 0^{\circ} n, \frac{- 4 x + 18 0 ^{\circ}}{4} = 18 0^{\circ} + 36 0^{\circ} n

\frac{- 4 x + 18 0 ^{\circ}}{4} = 0 + 36 0^{\circ} n, \frac{- 4 x + 18 0 ^{\circ}}{4} = 18 0^{\circ} + 36 0^{\circ} n

Solve

\frac{- 4 x + 18 0 ^{\circ}}{4} = 0 + 36 0^{\circ} n : x = - 36 0^{\circ} n + 4 5^{\circ}

\frac{- 4 x + 18 0 ^{\circ}}{4} = 0 + 36 0^{\circ} n

0 + 36 0^{\circ} n = 36 0^{\circ} n

\frac{- 4 x + 18 0 ^{\circ}}{4} = 36 0^{\circ} n

Multiply both sides by

4

\frac{- 4 x + 18 0 ^{\circ}}{4} = 36 0^{\circ} n

Multiply both sides by

4

\frac{4 ( - 4 x + 18 0 ^{\circ} )}{4} = 4 \cdot 36 0^{\circ} n

Simplify

- 4 x + 18 0^{\circ} = 144 0^{\circ} n

- 4 x + 18 0^{\circ} = 144 0^{\circ} n

Move

18 0^{\circ}

to the right side

- 4 x + 18 0^{\circ} = 144 0^{\circ} n

Subtract

18 0^{\circ}

from both sides

- 4 x + 18 0^{\circ} - 18 0^{\circ} = 144 0^{\circ} n - 18 0^{\circ}

Simplify

- 4 x = 144 0^{\circ} n - 18 0^{\circ}

- 4 x = 144 0^{\circ} n - 18 0^{\circ}

Divide both sides by

- 4

- 4 x = 144 0^{\circ} n - 18 0^{\circ}

Divide both sides by

- 4

\frac{- 4 x}{- 4} = \frac{144 0 ^{\circ} n}{- 4} - \frac{18 0 ^{\circ}}{- 4}

Simplify

\frac{- 4 x}{- 4} = \frac{144 0 ^{\circ} n}{- 4} - \frac{18 0 ^{\circ}}{- 4}

Simplify

\frac{- 4 x}{- 4} : x

\frac{- 4 x}{- 4}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{4 x}{4}

Divide the numbers:

\frac{4}{4} = 1

= x

Simplify

\frac{144 0 ^{\circ} n}{- 4} - \frac{18 0 ^{\circ}}{- 4} : - 36 0^{\circ} n + 4 5^{\circ}

\frac{144 0 ^{\circ} n}{- 4} - \frac{18 0 ^{\circ}}{- 4}

\frac{144 0 ^{\circ} n}{- 4} = - 36 0^{\circ} n

\frac{144 0 ^{\circ} n}{- 4}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{144 0 ^{\circ} n}{4}

Divide the numbers:

\frac{8}{4} = 2

= - 36 0^{\circ} n

= - 36 0^{\circ} n - \frac{18 0 ^{\circ}}{- 4}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - 36 0^{\circ} n - (- 4 5^{\circ})

Apply rule

- (- a) = a

= - 36 0^{\circ} n + 4 5^{\circ}

x = - 36 0^{\circ} n + 4 5^{\circ}

x = - 36 0^{\circ} n + 4 5^{\circ}

x = - 36 0^{\circ} n + 4 5^{\circ}

Solve

\frac{- 4 x + 18 0 ^{\circ}}{4} = 18 0^{\circ} + 36 0^{\circ} n : x = - 13 5^{\circ} - 36 0^{\circ} n

\frac{- 4 x + 18 0 ^{\circ}}{4} = 18 0^{\circ} + 36 0^{\circ} n

Multiply both sides by

4

\frac{- 4 x + 18 0 ^{\circ}}{4} = 18 0^{\circ} + 36 0^{\circ} n

Multiply both sides by

4

\frac{4 ( - 4 x + 18 0 ^{\circ} )}{4} = 72 0^{\circ} + 4 \cdot 36 0^{\circ} n

Simplify

- 4 x + 18 0^{\circ} = 72 0^{\circ} + 144 0^{\circ} n

- 4 x + 18 0^{\circ} = 72 0^{\circ} + 144 0^{\circ} n

Move

18 0^{\circ}

to the right side

- 4 x + 18 0^{\circ} = 72 0^{\circ} + 144 0^{\circ} n

Subtract

18 0^{\circ}

from both sides

- 4 x + 18 0^{\circ} - 18 0^{\circ} = 72 0^{\circ} + 144 0^{\circ} n - 18 0^{\circ}

Simplify

- 4 x = 54 0^{\circ} + 144 0^{\circ} n

- 4 x = 54 0^{\circ} + 144 0^{\circ} n

Divide both sides by

- 4

- 4 x = 54 0^{\circ} + 144 0^{\circ} n

Divide both sides by

- 4

\frac{- 4 x}{- 4} = \frac{54 0 ^{\circ}}{- 4} + \frac{144 0 ^{\circ} n}{- 4}

Simplify

\frac{- 4 x}{- 4} = \frac{54 0 ^{\circ}}{- 4} + \frac{144 0 ^{\circ} n}{- 4}

Simplify

\frac{- 4 x}{- 4} : x

\frac{- 4 x}{- 4}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{4 x}{4}

Divide the numbers:

\frac{4}{4} = 1

= x

Simplify

\frac{54 0 ^{\circ}}{- 4} + \frac{144 0 ^{\circ} n}{- 4} : - 13 5^{\circ} - 36 0^{\circ} n

\frac{54 0 ^{\circ}}{- 4} + \frac{144 0 ^{\circ} n}{- 4}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - 13 5^{\circ} + \frac{144 0 ^{\circ} n}{- 4}

\frac{144 0 ^{\circ} n}{- 4} = - 36 0^{\circ} n

\frac{144 0 ^{\circ} n}{- 4}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{144 0 ^{\circ} n}{4}

Divide the numbers:

\frac{8}{4} = 2

= - 36 0^{\circ} n

= - 13 5^{\circ} - 36 0^{\circ} n

x = - 13 5^{\circ} - 36 0^{\circ} n

x = - 13 5^{\circ} - 36 0^{\circ} n

x = - 13 5^{\circ} - 36 0^{\circ} n

x = - 36 0^{\circ} n + 4 5^{\circ}, x = - 13 5^{\circ} - 36 0^{\circ} n

Graph

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Frequently Asked Questions (FAQ)

What is the general solution for sin(x+2)=cos(x-2) ?
The general solution for sin(x+2)=cos(x-2) is x=-360n+45,x=-135-360n