What is the general solution for cos(y)=0.8192 ?

The general solution for cos(y)=0.8192 is y=0.61078…+2pin,y=2pi-0.61078…+2pin

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cos(y)=0.8192

cos (y) = 0.8192

y = 0.61078 \dots + 2 πn, y = 2 π - 0.61078 \dots + 2 πn

Degrees

y = 34.99520 \dots^{\circ} + 36 0^{\circ} n, y = 325.00479 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (y) = 0.8192

Apply trig inverse properties

cos (y) = 0.8192

General solutions for

cos (y) = 0.8192

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

y = arccos (0.8192) + 2 πn, y = 2 π - arccos (0.8192) + 2 πn

y = arccos (0.8192) + 2 πn, y = 2 π - arccos (0.8192) + 2 πn

Show solutions in decimal form

y = 0.61078 \dots + 2 πn, y = 2 π - 0.61078 \dots + 2 πn

x, 1.56 sin (2 x) = 2 \cdot sin (x) cos (x)

\frac{7}{sin ( 7 0 ^{\circ} )} = \frac{5}{sin ( b )}

6 cos^{2} (x) - 7 cos (x) + 2 = 0

csc (θ) = \frac{20}{4}

sin (x + 1 0^{\circ}) = cos (x + 2 0^{\circ})

What is the general solution for cos(y)=0.8192 ?
The general solution for cos(y)=0.8192 is y=0.61078…+2pin,y=2pi-0.61078…+2pin