What is the general solution for sin(b)= 2/3 ?

The general solution for sin(b)= 2/3 is b=0.72972…+2pin,b=pi-0.72972…+2pin

sin(b)= 2/3

sin (b) = \frac{2}{3}

b = 0.72972 \dots + 2 πn, b = π - 0.72972 \dots + 2 πn

Degrees

b = 41.81031 \dots^{\circ} + 36 0^{\circ} n, b = 138.18968 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (b) = \frac{2}{3}

Apply trig inverse properties

sin (b) = \frac{2}{3}

General solutions for

sin (b) = \frac{2}{3}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

b = arcsin (\frac{2}{3}) + 2 πn, b = π - arcsin (\frac{2}{3}) + 2 πn

b = arcsin (\frac{2}{3}) + 2 πn, b = π - arcsin (\frac{2}{3}) + 2 πn

Show solutions in decimal form

b = 0.72972 \dots + 2 πn, b = π - 0.72972 \dots + 2 πn

(- 5 cos (x) - 6 sin (x))^{2} - 11 sin^{2} (x) = 25

2 sin^{2} (x) - 9 sin (x) - 5 = 0

2 sin^{2} (x) = 5 cos (x) - 1

x, sec (x + 1 0^{\circ}) = 5.759

tan (x) cot (x) + 2 cot (x) = 0

What is the general solution for sin(b)= 2/3 ?
The general solution for sin(b)= 2/3 is b=0.72972…+2pin,b=pi-0.72972…+2pin