What is the general solution for cot(θ)+sqrt(3)=0,0<= θ<= 2pi ?

The general solution for cot(θ)+sqrt(3)=0,0<= θ<= 2pi is θ=(5pi)/6 ,θ=(11pi)/6

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cot(θ)+sqrt(3)=0,0<= θ<= 2pi

cot (θ) + 3 = 0, 0 \leq θ \leq 2 π

θ = \frac{5 π}{6}, θ = \frac{11 π}{6}

Degrees

θ = 15 0^{\circ}, θ = 33 0^{\circ}

Solution steps

cot (θ) + 3 = 0, 0 \leq θ \leq 2 π

Move

3

to the right side

cot (θ) + 3 = 0

Subtract

3

from both sides

cot (θ) + 3 - 3 = 0 - 3

Simplify

cot (θ) = - 3

cot (θ) = - 3

General solutions for

cot (θ) = - 3

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

θ = \frac{5 π}{6} + πn

θ = \frac{5 π}{6} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{5 π}{6}, θ = \frac{11 π}{6}

2 cos (θ) - 2 = 0, 0 \leq θ \leq 2 π

5 cos^{2} (x) + 14 sin (x) cos (x) = 3 sin^{2} (x)

4 cos^{2} (x) + 4 sin^{2} (x) - 5 = 0

4 sin^{2} (x) - 7 cos (x) = 2

x, 1 sin (2 5^{\circ}) = 1.51 sin (x)

What is the general solution for cot(θ)+sqrt(3)=0,0<= θ<= 2pi ?
The general solution for cot(θ)+sqrt(3)=0,0<= θ<= 2pi is θ=(5pi)/6 ,θ=(11pi)/6