What is the general solution for cos(θ)=-(sqrt(35))/6 ?

The general solution for cos(θ)=-(sqrt(35))/6 is θ=2.97414…+2pin,θ=-2.97414…+2pin

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cos(θ)=-(sqrt(35))/6

cos (θ) = - \frac{35}{6}

θ = 2.97414 \dots + 2 πn, θ = - 2.97414 \dots + 2 πn

Degrees

θ = 170.40593 \dots^{\circ} + 36 0^{\circ} n, θ = - 170.40593 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = - \frac{35}{6}

Apply trig inverse properties

cos (θ) = - \frac{35}{6}

General solutions for

cos (θ) = - \frac{35}{6}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

θ = arccos (- \frac{35}{6}) + 2 πn, θ = - arccos (- \frac{35}{6}) + 2 πn

θ = arccos (- \frac{35}{6}) + 2 πn, θ = - arccos (- \frac{35}{6}) + 2 πn

Show solutions in decimal form

θ = 2.97414 \dots + 2 πn, θ = - 2.97414 \dots + 2 πn

5 cos (x) + 2 sin (x) = 0

5 cos (x) + 2 sin (x) = 2

2 sin (2 x) = 0

2 cos (x) + cos (2 x) = 0

x, - sin (x + y) = 0

What is the general solution for cos(θ)=-(sqrt(35))/6 ?
The general solution for cos(θ)=-(sqrt(35))/6 is θ=2.97414…+2pin,θ=-2.97414…+2pin