What is the general solution for 1+cos(x)=1 ?

The general solution for 1+cos(x)=1 is x= pi/2+2pin,x=(3pi)/2+2pin

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1+cos(x)=1

1 + cos (x) = 1

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Degrees

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

1 + cos (x) = 1

Subtract

1

from both sides

1 + cos (x) - 1 = 1 - 1

Simplify

cos (x) = 0

General solutions for

cos (x) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

csc (x) sec (x) = tan (x)

sin^{4} (x) = 1 - cos^{4} (x)

8 cos (\frac{1}{2} x) + 4 = 0

5 sin (2 t) = 0

3 tan (3 x) + 3 = 0, 0^{\circ} \leq x \leq 18 0^{\circ}

What is the general solution for 1+cos(x)=1 ?
The general solution for 1+cos(x)=1 is x= pi/2+2pin,x=(3pi)/2+2pin