What is the general solution for 3tan(2x)-sqrt(3)=0 ?

The general solution for 3tan(2x)-sqrt(3)=0 is x= pi/(12)+(pin)/2

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3tan(2x)-sqrt(3)=0

3 tan (2 x) - 3 = 0

x = \frac{π}{12} + \frac{πn}{2}

Degrees

x = 1 5^{\circ} + 9 0^{\circ} n

Solution steps

3 tan (2 x) - 3 = 0

Move

3

to the right side

3 tan (2 x) - 3 = 0

Add

3

to both sides

3 tan (2 x) - 3 + 3 = 0 + 3

Simplify

3 tan (2 x) = 3

3 tan (2 x) = 3

Divide both sides by

3

3 tan (2 x) = 3

Divide both sides by

3

\frac{3 tan ( 2 x )}{3} = \frac{3}{3}

Simplify

tan (2 x) = \frac{3}{3}

tan (2 x) = \frac{3}{3}

General solutions for

tan (2 x) = \frac{3}{3}

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

2 x = \frac{π}{6} + πn

2 x = \frac{π}{6} + πn

Solve

2 x = \frac{π}{6} + πn : x = \frac{π}{12} + \frac{πn}{2}

2 x = \frac{π}{6} + πn

Divide both sides by

2

2 x = \frac{π}{6} + πn

Divide both sides by

2

\frac{2 x}{2} = \frac{\frac{π}{6}}{2} + \frac{πn}{2}

Simplify

\frac{2 x}{2} = \frac{\frac{π}{6}}{2} + \frac{πn}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{\frac{π}{6}}{2} + \frac{πn}{2} : \frac{π}{12} + \frac{πn}{2}

\frac{\frac{π}{6}}{2} + \frac{πn}{2}

\frac{\frac{π}{6}}{2} = \frac{π}{12}

\frac{\frac{π}{6}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{6 \cdot 2}

Multiply the numbers:

6 \cdot 2 = 12

= \frac{π}{12}

= \frac{π}{12} + \frac{πn}{2}

x = \frac{π}{12} + \frac{πn}{2}

x = \frac{π}{12} + \frac{πn}{2}

x = \frac{π}{12} + \frac{πn}{2}

x = \frac{π}{12} + \frac{πn}{2}

csc^{2} (x) = 3 cot (x) + 5

7^{2} + 2 5^{2} - 2 (7) (25) cos (x) = 2 4^{2}

tan (x) = 0.015

x, - sin (2 x) = 0

- 2 sin (x) - 2 sin (x) cos (x) = 0

What is the general solution for 3tan(2x)-sqrt(3)=0 ?
The general solution for 3tan(2x)-sqrt(3)=0 is x= pi/(12)+(pin)/2