What is the general solution for cos(32)=sin(5m)-12 ?

The general solution for cos(32)=sin(5m)-12 is No Solution for m\in\mathbb{R}

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cos(32)=sin(5m)-12

cos (3 2^{\circ}) = sin (5 m) - 12

No Solution for m \in R

Solution steps

cos (3 2^{\circ}) = sin (5 m) - 12

Switch sides

sin (5 m) - 12 = cos (3 2^{\circ})

Move

12

to the right side

sin (5 m) - 12 = cos (3 2^{\circ})

Add

12

to both sides

sin (5 m) - 12 + 12 = cos (3 2^{\circ}) + 12

Simplify

sin (5 m) = cos (3 2^{\circ}) + 12

sin (5 m) = cos (3 2^{\circ}) + 12

- 1 \leq sin (x) \leq 1

No Solution for m \in R

3 = 2 - 2 sin (θ)

sin (θ) = \frac{563}{2000}

6 sec (2 x) - 8 = 0

0 = cos (x) + cos (2 x)

8 cos^{2} (x) = 2

What is the general solution for cos(32)=sin(5m)-12 ?
The general solution for cos(32)=sin(5m)-12 is No Solution for m\in\mathbb{R}