What is the general solution for cos(t)=-5/13 ?

The general solution for cos(t)=-5/13 is t=1.96558…+2pin,t=-1.96558…+2pin

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cos(t)=-5/13

cos (t) = - \frac{5}{13}

t = 1.96558 \dots + 2 πn, t = - 1.96558 \dots + 2 πn

Degrees

t = 112.61986 \dots^{\circ} + 36 0^{\circ} n, t = - 112.61986 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (t) = - \frac{5}{13}

Apply trig inverse properties

cos (t) = - \frac{5}{13}

General solutions for

cos (t) = - \frac{5}{13}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

t = arccos (- \frac{5}{13}) + 2 πn, t = - arccos (- \frac{5}{13}) + 2 πn

t = arccos (- \frac{5}{13}) + 2 πn, t = - arccos (- \frac{5}{13}) + 2 πn

Show solutions in decimal form

t = 1.96558 \dots + 2 πn, t = - 1.96558 \dots + 2 πn

8 cos (x) = - 4

90 - 70 sin (x) - 130 cos (x) = 0

2 sin (x) sec (x) - 23 sin (x) = 0

cot (a) sec (a) = cos (a)

cos (2 x) 2 cos (x) = 2 (2 cos^{2} (x) - 1) 2 cos (x)

What is the general solution for cos(t)=-5/13 ?
The general solution for cos(t)=-5/13 is t=1.96558…+2pin,t=-1.96558…+2pin