What is the general solution for 2cos(t)=sqrt(3) ?

The general solution for 2cos(t)=sqrt(3) is t= pi/6+2pin,t=(11pi)/6+2pin

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2cos(t)=sqrt(3)

2 cos (t) = 3

t = \frac{π}{6} + 2 πn, t = \frac{11 π}{6} + 2 πn

Degrees

t = 3 0^{\circ} + 36 0^{\circ} n, t = 33 0^{\circ} + 36 0^{\circ} n

Solution steps

2 cos (t) = 3

Divide both sides by

2

2 cos (t) = 3

Divide both sides by

2

\frac{2 cos ( t )}{2} = \frac{3}{2}

Simplify

cos (t) = \frac{3}{2}

cos (t) = \frac{3}{2}

General solutions for

cos (t) = \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{6} + 2 πn, t = \frac{11 π}{6} + 2 πn

t = \frac{π}{6} + 2 πn, t = \frac{11 π}{6} + 2 πn

5 sin (x) = sin (x)

sin (3 x) = 3 sin (x)

cot^{2} (θ) + csc^{2} (θ) - 7 = 0

arcsin (x) + arcsin (2 x) = \frac{π}{3}

2 + cos (2 x) = - 5 sin (x), 0 \leq x \leq 2 π

What is the general solution for 2cos(t)=sqrt(3) ?
The general solution for 2cos(t)=sqrt(3) is t= pi/6+2pin,t=(11pi)/6+2pin