What is the general solution for tan(2x)= 4/3 ?

The general solution for tan(2x)= 4/3 is x=(0.92729…)/2+(pin)/2

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tan(2x)= 4/3

tan (2 x) = \frac{4}{3}

x = \frac{0.92729 \dots}{2} + \frac{πn}{2}

Degrees

x = 26.56505 \dots^{\circ} + 9 0^{\circ} n

Solution steps

tan (2 x) = \frac{4}{3}

Apply trig inverse properties

tan (2 x) = \frac{4}{3}

General solutions for

tan (2 x) = \frac{4}{3}

tan (x) = a \Rightarrow x = arctan (a) + πn

2 x = arctan (\frac{4}{3}) + πn

2 x = arctan (\frac{4}{3}) + πn

Solve

2 x = arctan (\frac{4}{3}) + πn : x = \frac{arctan ( \frac{4}{3} )}{2} + \frac{πn}{2}

2 x = arctan (\frac{4}{3}) + πn

Divide both sides by

2

2 x = arctan (\frac{4}{3}) + πn

Divide both sides by

2

\frac{2 x}{2} = \frac{arctan ( \frac{4}{3} )}{2} + \frac{πn}{2}

Simplify

x = \frac{arctan ( \frac{4}{3} )}{2} + \frac{πn}{2}

x = \frac{arctan ( \frac{4}{3} )}{2} + \frac{πn}{2}

x = \frac{arctan ( \frac{4}{3} )}{2} + \frac{πn}{2}

Show solutions in decimal form

x = \frac{0.92729 \dots}{2} + \frac{πn}{2}

sin (2 x) = \frac{( 9 m - 8 )}{2}

2 = 2 + 2 cos (θ)

cos (x) - 1 - 3 cos^{2} (x) = 0

tan (2 x) (16 cos^{4} (x) - 16 cos^{2} (x) + 3) = 0

x, y = sin (2 x)

What is the general solution for tan(2x)= 4/3 ?
The general solution for tan(2x)= 4/3 is x=(0.92729…)/2+(pin)/2