What is the general solution for arcsin(x)+arcsin(2x)= pi/3 ?

The general solution for arcsin(x)+arcsin(2x)= pi/3 is x=(sqrt(3))/(2sqrt(7))

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arcsin(x)+arcsin(2x)= pi/3

Solution

arcsin (x) + arcsin (2 x) = \frac{π}{3}

Solution

x = \frac{3}{2 7}

Solution steps

arcsin (x) + arcsin (2 x) = \frac{π}{3}

Rewrite using trig identities

arcsin (x) + arcsin (2 x)

Use the Sum to Product identity:

arcsin (s) + arcsin (t) = arcsin (s 1 - t^{2} + t 1 - s^{2})

= arcsin (x 1 - (2 x)^{2} + 2 x 1 - x^{2})

arcsin (x 1 - (2 x)^{2} + 2 x 1 - x^{2}) = \frac{π}{3}

Apply trig inverse properties

arcsin (x 1 - (2 x)^{2} + 2 x 1 - x^{2}) = \frac{π}{3}

arcsin (x) = a \Rightarrow x = sin (a)

x 1 - (2 x)^{2} + 2 x 1 - x^{2} = sin (\frac{π}{3})

sin (\frac{π}{3}) = \frac{3}{2}

sin (\frac{π}{3})

Use the following trivial identity:

sin (\frac{π}{3}) = \frac{3}{2}

sin (\frac{π}{3})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= \frac{3}{2}

x 1 - (2 x)^{2} + 2 x 1 - x^{2} = \frac{3}{2}

x 1 - (2 x)^{2} + 2 x 1 - x^{2} = \frac{3}{2}

Solve

x 1 - (2 x)^{2} + 2 x 1 - x^{2} = \frac{3}{2} : x = \frac{1}{2}, x = \frac{3}{2 7}

x 1 - (2 x)^{2} + 2 x 1 - x^{2} = \frac{3}{2}

Multiply both sides by

2

x 1 - (2 x)^{2} \cdot 2 + 2 x 1 - x^{2} \cdot 2 = \frac{3}{2} \cdot 2

Simplify

2 1 - (2 x)^{2} x + 4 1 - x^{2} x = 3

Remove square roots

2 1 - (2 x)^{2} x + 4 1 - x^{2} x = 3

Subtract

4 1 - x^{2} x

from both sides

2 1 - (2 x)^{2} x + 4 1 - x^{2} x - 4 1 - x^{2} x = 3 - 4 1 - x^{2} x

Simplify

2 1 - (2 x)^{2} x = 3 - 4 1 - x^{2} x

Square both sides:

4 x^{2} - 16 x^{4} = 3 - 83 x 1 - x^{2} + 16 x^{2} - 16 x^{4}

2 1 - (2 x)^{2} x + 4 1 - x^{2} x = 3

(2 1 - (2 x)^{2} x)^{2} = (3 - 4 1 - x^{2} x)^{2}

Expand

(2 1 - (2 x)^{2} x)^{2} : 4 x^{2} - 16 x^{4}

(2 1 - (2 x)^{2} x)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 2^{2} x^{2} (1 - (2 x)^{2})^{2}

(1 - (2 x)^{2})^{2} : 1 - (2 x)^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((1 - (2 x)^{2})^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (1 - (2 x)^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 1 - (2 x)^{2}

= 2^{2} (1 - (2 x)^{2}) x^{2}

2^{2} = 4

= 4 (1 - (2 x)^{2}) x^{2}

Expand

4 (1 - (2 x)^{2}) x^{2} : 4 x^{2} - 16 x^{4}

4 (1 - (2 x)^{2}) x^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 4 x^{2} (- 2^{2} x^{2} + 1)

2^{2} = 4

= 4 x^{2} (- 4 x^{2} + 1)

= 4 x^{2} (1 - 4 x^{2})

Apply the distributive law:

a (b - c) = ab - a c

a = 4 x^{2}, b = 1, c = 4 x^{2}

= 4 x^{2} \cdot 1 - 4 x^{2} \cdot 4 x^{2}

= 4 \cdot 1 \cdot x^{2} - 4 \cdot 4 x^{2} x^{2}

Simplify

4 \cdot 1 \cdot x^{2} - 4 \cdot 4 x^{2} x^{2} : 4 x^{2} - 16 x^{4}

4 \cdot 1 \cdot x^{2} - 4 \cdot 4 x^{2} x^{2}

4 \cdot 1 \cdot x^{2} = 4 x^{2}

4 \cdot 1 \cdot x^{2}

Multiply the numbers:

4 \cdot 1 = 4

= 4 x^{2}

4 \cdot 4 x^{2} x^{2} = 16 x^{4}

4 \cdot 4 x^{2} x^{2}

Multiply the numbers:

4 \cdot 4 = 16

= 16 x^{2} x^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{2} x^{2} = x^{2 + 2}

= 16 x^{2 + 2}

Add the numbers:

2 + 2 = 4

= 16 x^{4}

= 4 x^{2} - 16 x^{4}

= 4 x^{2} - 16 x^{4}

= 4 x^{2} - 16 x^{4}

Expand

(3 - 4 1 - x^{2} x)^{2} : 3 - 83 x 1 - x^{2} + 16 x^{2} - 16 x^{4}

(3 - 4 1 - x^{2} x)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = 3, b = 4 1 - x^{2} x

= (3)^{2} - 23 \cdot 4 1 - x^{2} x + (4 1 - x^{2} x)^{2}

Simplify

(3)^{2} - 23 \cdot 4 1 - x^{2} x + (4 1 - x^{2} x)^{2} : 3 - 83 1 - x^{2} x + 161 - x^{2} x^{2}

(3)^{2} - 23 \cdot 4 1 - x^{2} x + (4 1 - x^{2} x)^{2}

(3)^{2} = 3

(3)^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

23 \cdot 4 1 - x^{2} x = 83 1 - x^{2} x

23 \cdot 4 1 - x^{2} x

Multiply the numbers:

2 \cdot 4 = 8

= 83 1 - x^{2} x

(4 1 - x^{2} x)^{2} = 161 - x^{2} x^{2}

(4 1 - x^{2} x)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 4^{2} x^{2} (1 - x^{2})^{2}

(1 - x^{2})^{2} : 1 - x^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((1 - x^{2})^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (1 - x^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 1 - x^{2}

= 4^{2} (1 - x^{2}) x^{2}

4^{2} = 16

= 16 (1 - x^{2}) x^{2}

= 3 - 83 1 - x^{2} x + 16 (1 - x^{2}) x^{2}

= 3 - 83 1 - x^{2} x + 16 (1 - x^{2}) x^{2}

Expand

3 - 83 1 - x^{2} x + 16 (1 - x^{2}) x^{2} : 3 - 83 x 1 - x^{2} + 16 x^{2} - 16 x^{4}

3 - 83 1 - x^{2} x + 16 (1 - x^{2}) x^{2}

= 3 - 83 x 1 - x^{2} + 16 x^{2} (1 - x^{2})

Expand

16 x^{2} (1 - x^{2}) : 16 x^{2} - 16 x^{4}

16 x^{2} (1 - x^{2})

Apply the distributive law:

a (b - c) = ab - a c

a = 16 x^{2}, b = 1, c = x^{2}

= 16 x^{2} \cdot 1 - 16 x^{2} x^{2}

= 16 \cdot 1 \cdot x^{2} - 16 x^{2} x^{2}

Simplify

16 \cdot 1 \cdot x^{2} - 16 x^{2} x^{2} : 16 x^{2} - 16 x^{4}

16 \cdot 1 \cdot x^{2} - 16 x^{2} x^{2}

16 \cdot 1 \cdot x^{2} = 16 x^{2}

16 \cdot 1 \cdot x^{2}

Multiply the numbers:

16 \cdot 1 = 16

= 16 x^{2}

16 x^{2} x^{2} = 16 x^{4}

16 x^{2} x^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{2} x^{2} = x^{2 + 2}

= 16 x^{2 + 2}

Add the numbers:

2 + 2 = 4

= 16 x^{4}

= 16 x^{2} - 16 x^{4}

= 16 x^{2} - 16 x^{4}

= 3 - 83 1 - x^{2} x + 16 x^{2} - 16 x^{4}

= 3 - 83 x 1 - x^{2} + 16 x^{2} - 16 x^{4}

= 3 - 83 x 1 - x^{2} + 16 x^{2} - 16 x^{4}

4 x^{2} - 16 x^{4} = 3 - 83 x 1 - x^{2} + 16 x^{2} - 16 x^{4}

4 x^{2} - 16 x^{4} = 3 - 83 x 1 - x^{2} + 16 x^{2} - 16 x^{4}

Subtract

16 x^{2} - 16 x^{4}

from both sides

4 x^{2} - 16 x^{4} - (16 x^{2} - 16 x^{4}) = 3 - 83 x 1 - x^{2} + 16 x^{2} - 16 x^{4} - (16 x^{2} - 16 x^{4})

Simplify

- 12 x^{2} = - 83 1 - x^{2} x + 3

Subtract

3

from both sides

- 12 x^{2} - 3 = - 83 1 - x^{2} x + 3 - 3

Simplify

- 12 x^{2} - 3 = - 83 1 - x^{2} x

Square both sides:

144 x^{4} + 72 x^{2} + 9 = 192 x^{2} - 192 x^{4}

4 x^{2} - 16 x^{4} = 3 - 83 x 1 - x^{2} + 16 x^{2} - 16 x^{4}

(- 12 x^{2} - 3)^{2} = (- 83 1 - x^{2} x)^{2}

Expand

(- 12 x^{2} - 3)^{2} : 144 x^{4} + 72 x^{2} + 9

(- 12 x^{2} - 3)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = - 12 x^{2}, b = 3

= (- 12 x^{2})^{2} - 2 (- 12 x^{2}) \cdot 3 + 3^{2}

Simplify

(- 12 x^{2})^{2} - 2 (- 12 x^{2}) \cdot 3 + 3^{2} : 144 x^{4} + 72 x^{2} + 9

(- 12 x^{2})^{2} - 2 (- 12 x^{2}) \cdot 3 + 3^{2}

Apply rule

- (- a) = a

= (- 12 x^{2})^{2} + 2 \cdot 12 x^{2} \cdot 3 + 3^{2}

(- 12 x^{2})^{2} = 144 x^{4}

(- 12 x^{2})^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 12 x^{2})^{2} = (12 x^{2})^{2}

= (12 x^{2})^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 1 2^{2} (x^{2})^{2}

(x^{2})^{2} : x^{4}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= x^{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= x^{4}

= 1 2^{2} x^{4}

1 2^{2} = 144

= 144 x^{4}

2 \cdot 12 x^{2} \cdot 3 = 72 x^{2}

2 \cdot 12 x^{2} \cdot 3

Multiply the numbers:

2 \cdot 12 \cdot 3 = 72

= 72 x^{2}

3^{2} = 9

3^{2}

3^{2} = 9

= 9

= 144 x^{4} + 72 x^{2} + 9

= 144 x^{4} + 72 x^{2} + 9

Expand

(- 83 1 - x^{2} x)^{2} : 192 x^{2} - 192 x^{4}

(- 83 1 - x^{2} x)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 83 1 - x^{2} x)^{2} = (83 1 - x^{2} x)^{2}

= (83 1 - x^{2} x)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 8^{2} (3)^{2} x^{2} (1 - x^{2})^{2}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= 8^{2} \cdot 3 (1 - x^{2})^{2} x^{2}

(1 - x^{2})^{2} : 1 - x^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((1 - x^{2})^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (1 - x^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 1 - x^{2}

= 8^{2} \cdot 3 (1 - x^{2}) x^{2}

Refine

= 192 (1 - x^{2}) x^{2}

Expand

192 (1 - x^{2}) x^{2} : 192 x^{2} - 192 x^{4}

192 (1 - x^{2}) x^{2}

= 192 x^{2} (1 - x^{2})

Apply the distributive law:

a (b - c) = ab - a c

a = 192 x^{2}, b = 1, c = x^{2}

= 192 x^{2} \cdot 1 - 192 x^{2} x^{2}

= 192 \cdot 1 \cdot x^{2} - 192 x^{2} x^{2}

Simplify

192 \cdot 1 \cdot x^{2} - 192 x^{2} x^{2} : 192 x^{2} - 192 x^{4}

192 \cdot 1 \cdot x^{2} - 192 x^{2} x^{2}

192 \cdot 1 \cdot x^{2} = 192 x^{2}

192 \cdot 1 \cdot x^{2}

Multiply the numbers:

192 \cdot 1 = 192

= 192 x^{2}

192 x^{2} x^{2} = 192 x^{4}

192 x^{2} x^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{2} x^{2} = x^{2 + 2}

= 192 x^{2 + 2}

Add the numbers:

2 + 2 = 4

= 192 x^{4}

= 192 x^{2} - 192 x^{4}

= 192 x^{2} - 192 x^{4}

= 192 x^{2} - 192 x^{4}

144 x^{4} + 72 x^{2} + 9 = 192 x^{2} - 192 x^{4}

144 x^{4} + 72 x^{2} + 9 = 192 x^{2} - 192 x^{4}

144 x^{4} + 72 x^{2} + 9 = 192 x^{2} - 192 x^{4}

Solve

144 x^{4} + 72 x^{2} + 9 = 192 x^{2} - 192 x^{4} : x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{3}{2 7}, x = - \frac{3}{2 7}

144 x^{4} + 72 x^{2} + 9 = 192 x^{2} - 192 x^{4}

Move

192 x^{4}

to the left side

144 x^{4} + 72 x^{2} + 9 = 192 x^{2} - 192 x^{4}

Add

192 x^{4}

to both sides

144 x^{4} + 72 x^{2} + 9 + 192 x^{4} = 192 x^{2} - 192 x^{4} + 192 x^{4}

Simplify

336 x^{4} + 72 x^{2} + 9 = 192 x^{2}

336 x^{4} + 72 x^{2} + 9 = 192 x^{2}

Move

192 x^{2}

to the left side

336 x^{4} + 72 x^{2} + 9 = 192 x^{2}

Subtract

192 x^{2}

from both sides

336 x^{4} + 72 x^{2} + 9 - 192 x^{2} = 192 x^{2} - 192 x^{2}

Simplify

336 x^{4} - 120 x^{2} + 9 = 0

336 x^{4} - 120 x^{2} + 9 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

336 u^{2} - 120 u + 9 = 0

Solve

336 u^{2} - 120 u + 9 = 0 : u = \frac{1}{4}, u = \frac{3}{28}

336 u^{2} - 120 u + 9 = 0

Solve with the quadratic formula

336 u^{2} - 120 u + 9 = 0

Quadratic Equation Formula:

For

a = 336, b = - 120, c = 9

u_{1, 2} = \frac{- ( - 120 ) \pm ( - 120 ) ^{2} - 4 \cdot 336 \cdot 9}{2 \cdot 336}

u_{1, 2} = \frac{- ( - 120 ) \pm ( - 120 ) ^{2} - 4 \cdot 336 \cdot 9}{2 \cdot 336}

(- 120)^{2} - 4 \cdot 336 \cdot 9 = 48

(- 120)^{2} - 4 \cdot 336 \cdot 9

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 120)^{2} = 12 0^{2}

= 12 0^{2} - 4 \cdot 336 \cdot 9

Multiply the numbers:

4 \cdot 336 \cdot 9 = 12096

= 12 0^{2} - 12096

12 0^{2} = 14400

= 14400 - 12096

Subtract the numbers:

14400 - 12096 = 2304

= 2304

Factor the number:

2304 = 4 8^{2}

= 4 8^{2}

Apply radical rule:

4 8^{2} = 48

= 48

u_{1, 2} = \frac{- ( - 120 ) \pm 48}{2 \cdot 336}

Separate the solutions

u_{1} = \frac{- ( - 120 ) + 48}{2 \cdot 336}, u_{2} = \frac{- ( - 120 ) - 48}{2 \cdot 336}

u = \frac{- ( - 120 ) + 48}{2 \cdot 336} : \frac{1}{4}

\frac{- ( - 120 ) + 48}{2 \cdot 336}

Apply rule

- (- a) = a

= \frac{120 + 48}{2 \cdot 336}

Add the numbers:

120 + 48 = 168

= \frac{168}{2 \cdot 336}

Multiply the numbers:

2 \cdot 336 = 672

= \frac{168}{672}

Cancel the common factor:

168

= \frac{1}{4}

u = \frac{- ( - 120 ) - 48}{2 \cdot 336} : \frac{3}{28}

\frac{- ( - 120 ) - 48}{2 \cdot 336}

Apply rule

- (- a) = a

= \frac{120 - 48}{2 \cdot 336}

Subtract the numbers:

120 - 48 = 72

= \frac{72}{2 \cdot 336}

Multiply the numbers:

2 \cdot 336 = 672

= \frac{72}{672}

Cancel the common factor:

24

= \frac{3}{28}

The solutions to the quadratic equation are:

u = \frac{1}{4}, u = \frac{3}{28}

u = \frac{1}{4}, u = \frac{3}{28}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{1}{4} : x = \frac{1}{2}, x = - \frac{1}{2}

x^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{4}, x = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

\frac{1}{4}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= \frac{1}{4}

Apply radical rule:

1 = 1

1 = 1

= \frac{1}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

a^{2} = a, a \geq 0

2^{2} = 2

= 2

= \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

- \frac{1}{4}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= - \frac{1}{4}

Apply radical rule:

1 = 1

1 = 1

= - \frac{1}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

a^{2} = a, a \geq 0

2^{2} = 2

= 2

= - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Solve

x^{2} = \frac{3}{28} : x = \frac{3}{2 7}, x = - \frac{3}{2 7}

x^{2} = \frac{3}{28}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{28}, x = - \frac{3}{28}

\frac{3}{28} = \frac{3}{2 7}

\frac{3}{28}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= \frac{3}{28}

28 = 27

28

Prime factorization of

28 : 2^{2} \cdot 7

28

28

divides by

228 = 14 \cdot 2

= 2 \cdot 14

14

divides by

214 = 7 \cdot 2

= 2 \cdot 2 \cdot 7

2, 7

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 7

= 2^{2} \cdot 7

= 2^{2} \cdot 7

Apply radical rule:

ab = a b, a \geq 0, b \geq 0

2^{2} \cdot 7 = 2^{2} 7

= 2^{2} 7

Apply radical rule:

a^{2} = a, a \geq 0

2^{2} = 2

= 27

= \frac{3}{2 7}

- \frac{3}{28} = - \frac{3}{2 7}

- \frac{3}{28}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= - \frac{3}{28}

28 = 27

28

Prime factorization of

28 : 2^{2} \cdot 7

28

28

divides by

228 = 14 \cdot 2

= 2 \cdot 14

14

divides by

214 = 7 \cdot 2

= 2 \cdot 2 \cdot 7

2, 7

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 7

= 2^{2} \cdot 7

= 2^{2} \cdot 7

Apply radical rule:

ab = a b, a \geq 0, b \geq 0

2^{2} \cdot 7 = 2^{2} 7

= 2^{2} 7

Apply radical rule:

a^{2} = a, a \geq 0

2^{2} = 2

= 27

= - \frac{3}{2 7}

x = \frac{3}{2 7}, x = - \frac{3}{2 7}

The solutions are

x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{3}{2 7}, x = - \frac{3}{2 7}

x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{3}{2 7}, x = - \frac{3}{2 7}

Verify Solutions:

x = \frac{1}{2}

True

, x = - \frac{1}{2}

False

, x = \frac{3}{2 7}

True

, x = - \frac{3}{2 7}

False

Check the solutions by plugging them into

x 1 - (2 x)^{2} + 2 x 1 - x^{2} = \frac{3}{2}

Remove the ones that don't agree with the equation.

Plug in

x = \frac{1}{2} :

True

(\frac{1}{2}) 1 - (2 (\frac{1}{2}))^{2} + 2 (\frac{1}{2}) 1 - (\frac{1}{2})^{2} = \frac{3}{2}

(\frac{1}{2}) 1 - (2 (\frac{1}{2}))^{2} + 2 (\frac{1}{2}) 1 - (\frac{1}{2})^{2} = \frac{3}{2}

(\frac{1}{2}) 1 - (2 (\frac{1}{2}))^{2} + 2 (\frac{1}{2}) 1 - (\frac{1}{2})^{2}

Remove parentheses:

(a) = a

= \frac{1}{2} 1 - (2 \cdot \frac{1}{2})^{2} + 2 \cdot \frac{1}{2} 1 - (\frac{1}{2})^{2}

\frac{1}{2} 1 - (2 \cdot \frac{1}{2})^{2} = 0

\frac{1}{2} 1 - (2 \cdot \frac{1}{2})^{2}

1 - (2 \cdot \frac{1}{2})^{2} = 0

1 - (2 \cdot \frac{1}{2})^{2}

(2 \cdot \frac{1}{2})^{2} = 1

(2 \cdot \frac{1}{2})^{2}

Multiply

2 \cdot \frac{1}{2} : 1

2 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 1^{2}

Apply rule

1^{a} = 1

= 1

= 1 - 1

Subtract the numbers:

1 - 1 = 0

= 0

Apply rule

0 = 0

= 0

= 0 \cdot \frac{1}{2}

Apply rule

0 \cdot a = 0

= 0

2 \cdot \frac{1}{2} 1 - (\frac{1}{2})^{2} = \frac{3}{2}

2 \cdot \frac{1}{2} 1 - (\frac{1}{2})^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 1 - ( \frac{1}{2} ) ^{2}}{2}

Cancel the common factor:

2

= 1 \cdot 1 - (\frac{1}{2})^{2}

1 - (\frac{1}{2})^{2} = \frac{3}{2}

1 - (\frac{1}{2})^{2}

(\frac{1}{2})^{2} = \frac{1}{4}

(\frac{1}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{2 ^{2}}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{2 ^{2}}

2^{2} = 4

= \frac{1}{4}

= 1 - \frac{1}{4}

Join

1 - \frac{1}{4} : \frac{3}{4}

1 - \frac{1}{4}

Convert element to fraction:

1 = \frac{1 \cdot 4}{4}

= \frac{1 \cdot 4}{4} - \frac{1}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 4 - 1}{4}

1 \cdot 4 - 1 = 3

1 \cdot 4 - 1

Multiply the numbers:

1 \cdot 4 = 4

= 4 - 1

Subtract the numbers:

4 - 1 = 3

= 3

= \frac{3}{4}

= \frac{3}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{3}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{3}{2}

= 1 \cdot \frac{3}{2}

Multiply:

1 \cdot \frac{3}{2} = \frac{3}{2}

= \frac{3}{2}

= 0 + \frac{3}{2}

0 + \frac{3}{2} = \frac{3}{2}

= \frac{3}{2}

\frac{3}{2} = \frac{3}{2}

True

Plug in

x = - \frac{1}{2} :

False

(- \frac{1}{2}) 1 - (2 (- \frac{1}{2}))^{2} + 2 (- \frac{1}{2}) 1 - (- \frac{1}{2})^{2} = \frac{3}{2}

(- \frac{1}{2}) 1 - (2 (- \frac{1}{2}))^{2} + 2 (- \frac{1}{2}) 1 - (- \frac{1}{2})^{2} = - \frac{3}{2}

(- \frac{1}{2}) 1 - (2 (- \frac{1}{2}))^{2} + 2 (- \frac{1}{2}) 1 - (- \frac{1}{2})^{2}

Remove parentheses:

(- a) = - a

= - \frac{1}{2} 1 - (- 2 \cdot \frac{1}{2})^{2} - 2 \cdot \frac{1}{2} 1 - (- \frac{1}{2})^{2}

\frac{1}{2} 1 - (- 2 \cdot \frac{1}{2})^{2} = 0

\frac{1}{2} 1 - (- 2 \cdot \frac{1}{2})^{2}

1 - (- 2 \cdot \frac{1}{2})^{2} = 0

1 - (- 2 \cdot \frac{1}{2})^{2}

(- 2 \cdot \frac{1}{2})^{2} = 1

(- 2 \cdot \frac{1}{2})^{2}

Multiply

- 2 \cdot \frac{1}{2} : - 1

- 2 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= - 1

= (- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2}

= 1^{2}

Apply rule

1^{a} = 1

= 1

= 1 - 1

Subtract the numbers:

1 - 1 = 0

= 0

Apply rule

0 = 0

= 0

= 0 \cdot \frac{1}{2}

Apply rule

0 \cdot a = 0

= 0

2 \cdot \frac{1}{2} 1 - (- \frac{1}{2})^{2} = \frac{3}{2}

2 \cdot \frac{1}{2} 1 - (- \frac{1}{2})^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 1 - ( - \frac{1}{2} ) ^{2}}{2}

Cancel the common factor:

2

= 1 \cdot 1 - (- \frac{1}{2})^{2}

1 - (- \frac{1}{2})^{2} = \frac{3}{2}

1 - (- \frac{1}{2})^{2}

(- \frac{1}{2})^{2} = \frac{1}{4}

(- \frac{1}{2})^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{1}{2})^{2} = (\frac{1}{2})^{2}

= (\frac{1}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{2 ^{2}}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{2 ^{2}}

2^{2} = 4

= \frac{1}{4}

= 1 - \frac{1}{4}

Join

1 - \frac{1}{4} : \frac{3}{4}

1 - \frac{1}{4}

Convert element to fraction:

1 = \frac{1 \cdot 4}{4}

= \frac{1 \cdot 4}{4} - \frac{1}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 4 - 1}{4}

1 \cdot 4 - 1 = 3

1 \cdot 4 - 1

Multiply the numbers:

1 \cdot 4 = 4

= 4 - 1

Subtract the numbers:

4 - 1 = 3

= 3

= \frac{3}{4}

= \frac{3}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{3}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{3}{2}

= 1 \cdot \frac{3}{2}

Multiply:

1 \cdot \frac{3}{2} = \frac{3}{2}

= \frac{3}{2}

= - 0 - \frac{3}{2}

- 0 - \frac{3}{2} = - \frac{3}{2}

= - \frac{3}{2}

- \frac{3}{2} = \frac{3}{2}

False

Plug in

x = \frac{3}{2 7} :

True

(\frac{3}{2 7}) 1 - (2 (\frac{3}{2 7}))^{2} + 2 (\frac{3}{2 7}) 1 - (\frac{3}{2 7})^{2} = \frac{3}{2}

(\frac{3}{2 7}) 1 - (2 (\frac{3}{2 7}))^{2} + 2 (\frac{3}{2 7}) 1 - (\frac{3}{2 7})^{2} = \frac{3}{2}

(\frac{3}{2 7}) 1 - (2 (\frac{3}{2 7}))^{2} + 2 (\frac{3}{2 7}) 1 - (\frac{3}{2 7})^{2}

Remove parentheses:

(a) = a

= \frac{3}{2 7} 1 - (2 \cdot \frac{3}{2 7})^{2} + 2 \cdot \frac{3}{2 7} 1 - (\frac{3}{2 7})^{2}

\frac{3}{2 7} 1 - (2 \cdot \frac{3}{2 7})^{2} = \frac{3}{7}

\frac{3}{2 7} 1 - (2 \cdot \frac{3}{2 7})^{2}

1 - (2 \cdot \frac{3}{2 7})^{2} = \frac{2}{7}

1 - (2 \cdot \frac{3}{2 7})^{2}

(2 \cdot \frac{3}{2 7})^{2} = \frac{3}{7}

(2 \cdot \frac{3}{2 7})^{2}

Multiply

2 \cdot \frac{3}{2 7} : \frac{3}{7}

2 \cdot \frac{3}{2 7}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 2}{2 7}

Cancel the common factor:

2

= \frac{3}{7}

Combine same powers :

\frac{x}{y} = \frac{x}{y}

= \frac{3}{7}

= (\frac{3}{7})^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((\frac{3}{7})^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (\frac{3}{7})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= \frac{3}{7}

= 1 - \frac{3}{7}

Join

1 - \frac{3}{7} : \frac{4}{7}

1 - \frac{3}{7}

Convert element to fraction:

1 = \frac{1 \cdot 7}{7}

= \frac{1 \cdot 7}{7} - \frac{3}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 7 - 3}{7}

1 \cdot 7 - 3 = 4

1 \cdot 7 - 3

Multiply the numbers:

1 \cdot 7 = 7

= 7 - 3

Subtract the numbers:

7 - 3 = 4

= 4

= \frac{4}{7}

= \frac{4}{7}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{4}{7}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{2}{7}

= \frac{2}{7} \cdot \frac{3}{2 7}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 2}{2 7 7}

Cancel the common factor:

2

= \frac{3}{7 7}

77 = 7

77

Apply radical rule:

a a = a

77 = 7

= 7

= \frac{3}{7}

2 \cdot \frac{3}{2 7} 1 - (\frac{3}{2 7})^{2} = \frac{5 3}{14}

2 \cdot \frac{3}{2 7} 1 - (\frac{3}{2 7})^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 2 1 - ( \frac{3}{2 7} ) ^{2}}{2 7}

Cancel the common factor:

2

= \frac{3 1 - ( \frac{3}{2 7} ) ^{2}}{7}

1 - (\frac{3}{2 7})^{2} = \frac{5}{2 7}

1 - (\frac{3}{2 7})^{2}

(\frac{3}{2 7})^{2} = \frac{3}{28}

(\frac{3}{2 7})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 ) ^{2}}{( 2 7 ) ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(27)^{2} = 2^{2} (7)^{2}

= \frac{( 3 ) ^{2}}{2 ^{2} ( 7 ) ^{2}}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= \frac{3}{2 ^{2} ( 7 ) ^{2}}

(7)^{2} : 7

Apply radical rule:

a = a^{\frac{1}{2}}

= (7^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 7^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 7

= \frac{3}{2 ^{2} \cdot 7}

2^{2} \cdot 7 = 28

2^{2} \cdot 7

2^{2} = 4

= 4 \cdot 7

Multiply the numbers:

4 \cdot 7 = 28

= 28

= \frac{3}{28}

= 1 - \frac{3}{28}

Join

1 - \frac{3}{28} : \frac{25}{28}

1 - \frac{3}{28}

Convert element to fraction:

1 = \frac{1 \cdot 28}{28}

= \frac{1 \cdot 28}{28} - \frac{3}{28}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 28 - 3}{28}

1 \cdot 28 - 3 = 25

1 \cdot 28 - 3

Multiply the numbers:

1 \cdot 28 = 28

= 28 - 3

Subtract the numbers:

28 - 3 = 25

= 25

= \frac{25}{28}

= \frac{25}{28}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{25}{28}

28 = 27

28

Prime factorization of

28 : 2^{2} \cdot 7

28

28

divides by

228 = 14 \cdot 2

= 2 \cdot 14

14

divides by

214 = 7 \cdot 2

= 2 \cdot 2 \cdot 7

2, 7

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 7

= 2^{2} \cdot 7

= 2^{2} \cdot 7

Apply radical rule:

= 7 2^{2}

Apply radical rule:

2^{2} = 2

= 27

= \frac{25}{2 7}

25 = 5

25

Factor the number:

25 = 5^{2}

= 5^{2}

Apply radical rule:

5^{2} = 5

= 5

= \frac{5}{2 7}

= \frac{3 \frac{5}{2 7}}{7}

Multiply

3 \frac{5}{2 7} : \frac{5 3}{2 7}

3 \frac{5}{2 7}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{5 3}{2 7}

= \frac{\frac{5 3}{2 7}}{7}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 3}{2 7 7}

277 = 14

277

Apply radical rule:

a a = a

77 = 7

= 2 \cdot 7

Multiply the numbers:

2 \cdot 7 = 14

= 14

= \frac{5 3}{14}

= \frac{3}{7} + \frac{5 3}{14}

Least Common Multiplier of

7, 14 : 14

7, 14

Least Common Multiplier (LCM)

Prime factorization of

7 : 7

7

7

is a prime number, therefore no factorization is possible

= 7

Prime factorization of

14 : 2 \cdot 7

14

14

divides by

214 = 7 \cdot 2

= 2 \cdot 7

2, 7

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 7

Multiply each factor the greatest number of times it occurs in either

7

14

= 7 \cdot 2

Multiply the numbers:

7 \cdot 2 = 14

= 14

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

14

For

\frac{3}{7} :

multiply the denominator and numerator by

2

\frac{3}{7} = \frac{3 \cdot 2}{7 \cdot 2} = \frac{3 \cdot 2}{14}

= \frac{3 \cdot 2}{14} + \frac{5 3}{14}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 2 + 5 3}{14}

Add similar elements:

23 + 53 = 73

= \frac{7 3}{14}

Cancel the common factor:

7

= \frac{3}{2}

\frac{3}{2} = \frac{3}{2}

True

Plug in

x = - \frac{3}{2 7} :

False

(- \frac{3}{2 7}) 1 - (2 (- \frac{3}{2 7}))^{2} + 2 (- \frac{3}{2 7}) 1 - (- \frac{3}{2 7})^{2} = \frac{3}{2}

(- \frac{3}{2 7}) 1 - (2 (- \frac{3}{2 7}))^{2} + 2 (- \frac{3}{2 7}) 1 - (- \frac{3}{2 7})^{2} = - \frac{3}{2}

(- \frac{3}{2 7}) 1 - (2 (- \frac{3}{2 7}))^{2} + 2 (- \frac{3}{2 7}) 1 - (- \frac{3}{2 7})^{2}

Remove parentheses:

(- a) = - a

= - \frac{3}{2 7} 1 - (- 2 \cdot \frac{3}{2 7})^{2} - 2 \cdot \frac{3}{2 7} 1 - (- \frac{3}{2 7})^{2}

\frac{3}{2 7} 1 - (- 2 \cdot \frac{3}{2 7})^{2} = \frac{3}{7}

\frac{3}{2 7} 1 - (- 2 \cdot \frac{3}{2 7})^{2}

1 - (- 2 \cdot \frac{3}{2 7})^{2} = \frac{2}{7}

1 - (- 2 \cdot \frac{3}{2 7})^{2}

(- 2 \cdot \frac{3}{2 7})^{2} = \frac{3}{7}

(- 2 \cdot \frac{3}{2 7})^{2}

Multiply

- 2 \cdot \frac{3}{2 7} : - \frac{3}{7}

- 2 \cdot \frac{3}{2 7}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{3 \cdot 2}{2 7}

Cancel the common factor:

2

= - \frac{3}{7}

Combine same powers :

\frac{x}{y} = \frac{x}{y}

= - \frac{3}{7}

= (- \frac{3}{7})^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{3}{7})^{2} = (\frac{3}{7})^{2}

= (\frac{3}{7})^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((\frac{3}{7})^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (\frac{3}{7})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= \frac{3}{7}

= 1 - \frac{3}{7}

Join

1 - \frac{3}{7} : \frac{4}{7}

1 - \frac{3}{7}

Convert element to fraction:

1 = \frac{1 \cdot 7}{7}

= \frac{1 \cdot 7}{7} - \frac{3}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 7 - 3}{7}

1 \cdot 7 - 3 = 4

1 \cdot 7 - 3

Multiply the numbers:

1 \cdot 7 = 7

= 7 - 3

Subtract the numbers:

7 - 3 = 4

= 4

= \frac{4}{7}

= \frac{4}{7}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{4}{7}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{2}{7}

= \frac{2}{7} \cdot \frac{3}{2 7}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 2}{2 7 7}

Cancel the common factor:

2

= \frac{3}{7 7}

77 = 7

77

Apply radical rule:

a a = a

77 = 7

= 7

= \frac{3}{7}

2 \cdot \frac{3}{2 7} 1 - (- \frac{3}{2 7})^{2} = \frac{5 3}{14}

2 \cdot \frac{3}{2 7} 1 - (- \frac{3}{2 7})^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 2 1 - ( - \frac{3}{2 7} ) ^{2}}{2 7}

Cancel the common factor:

2

= \frac{3 1 - ( - \frac{3}{2 7} ) ^{2}}{7}

3 1 - (- \frac{3}{2 7})^{2} = 3 1 - (\frac{3}{2 7})^{2}

3 1 - (- \frac{3}{2 7})^{2}

1 - (- \frac{3}{2 7})^{2} = 1 - (\frac{3}{2 7})^{2}

1 - (- \frac{3}{2 7})^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{3}{2 7})^{2} = (\frac{3}{2 7})^{2}

= 1 - (\frac{3}{2 7})^{2}

= 3 - (\frac{3}{2 7})^{2} + 1

= \frac{3 - ( \frac{3}{2 7} ) ^{2} + 1}{7}

1 - (\frac{3}{2 7})^{2} = \frac{5}{2 7}

1 - (\frac{3}{2 7})^{2}

(\frac{3}{2 7})^{2} = \frac{3}{28}

(\frac{3}{2 7})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 ) ^{2}}{( 2 7 ) ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(27)^{2} = 2^{2} (7)^{2}

= \frac{( 3 ) ^{2}}{2 ^{2} ( 7 ) ^{2}}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= \frac{3}{2 ^{2} ( 7 ) ^{2}}

(7)^{2} : 7

Apply radical rule:

a = a^{\frac{1}{2}}

= (7^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 7^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 7

= \frac{3}{2 ^{2} \cdot 7}

2^{2} \cdot 7 = 28

2^{2} \cdot 7

2^{2} = 4

= 4 \cdot 7

Multiply the numbers:

4 \cdot 7 = 28

= 28

= \frac{3}{28}

= 1 - \frac{3}{28}

Join

1 - \frac{3}{28} : \frac{25}{28}

1 - \frac{3}{28}

Convert element to fraction:

1 = \frac{1 \cdot 28}{28}

= \frac{1 \cdot 28}{28} - \frac{3}{28}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 28 - 3}{28}

1 \cdot 28 - 3 = 25

1 \cdot 28 - 3

Multiply the numbers:

1 \cdot 28 = 28

= 28 - 3

Subtract the numbers:

28 - 3 = 25

= 25

= \frac{25}{28}

= \frac{25}{28}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{25}{28}

28 = 27

28

Prime factorization of

28 : 2^{2} \cdot 7

28

28

divides by

228 = 14 \cdot 2

= 2 \cdot 14

14

divides by

214 = 7 \cdot 2

= 2 \cdot 2 \cdot 7

2, 7

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 7

= 2^{2} \cdot 7

= 2^{2} \cdot 7

Apply radical rule:

= 7 2^{2}

Apply radical rule:

2^{2} = 2

= 27

= \frac{25}{2 7}

25 = 5

25

Factor the number:

25 = 5^{2}

= 5^{2}

Apply radical rule:

5^{2} = 5

= 5

= \frac{5}{2 7}

= \frac{3 \frac{5}{2 7}}{7}

Multiply

3 \frac{5}{2 7} : \frac{5 3}{2 7}

3 \frac{5}{2 7}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{5 3}{2 7}

= \frac{\frac{5 3}{2 7}}{7}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 3}{2 7 7}

277 = 14

277

Apply radical rule:

a a = a

77 = 7

= 2 \cdot 7

Multiply the numbers:

2 \cdot 7 = 14

= 14

= \frac{5 3}{14}

= - \frac{3}{7} - \frac{5 3}{14}

Least Common Multiplier of

7, 14 : 14

7, 14

Least Common Multiplier (LCM)

Prime factorization of

7 : 7

7

7

is a prime number, therefore no factorization is possible

= 7

Prime factorization of

14 : 2 \cdot 7

14

14

divides by

214 = 7 \cdot 2

= 2 \cdot 7

2, 7

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 7

Multiply each factor the greatest number of times it occurs in either

7

14

= 7 \cdot 2

Multiply the numbers:

7 \cdot 2 = 14

= 14

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

14

For

\frac{3}{7} :

multiply the denominator and numerator by

2

\frac{3}{7} = \frac{3 \cdot 2}{7 \cdot 2} = \frac{3 \cdot 2}{14}

= - \frac{3 \cdot 2}{14} - \frac{5 3}{14}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 \cdot 2 - 5 3}{14}

Add similar elements:

- 23 - 53 = - 73

= \frac{- 7 3}{14}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{7 3}{14}

Cancel the common factor:

7

= - \frac{3}{2}

- \frac{3}{2} = \frac{3}{2}

False

The solutions are

x = \frac{1}{2}, x = \frac{3}{2 7}

x = \frac{1}{2}, x = \frac{3}{2 7}

Verify solutions by plugging them into the original equation

Check the solutions by plugging them into

arcsin (x) + arcsin (2 x) = \frac{π}{3}

Remove the ones that don't agree with the equation.

Check the solution

\frac{1}{2} :

False

\frac{1}{2}

Plug in

n = 1

\frac{1}{2}

For

arcsin (x) + arcsin (2 x) = \frac{π}{3}

plug in

x = \frac{1}{2}

arcsin (\frac{1}{2}) + arcsin (2 \cdot \frac{1}{2}) = \frac{π}{3}

Refine

2.09439 \dots = 1.04719 \dots

\Rightarrow False

Check the solution

\frac{3}{2 7} :

True

\frac{3}{2 7}

Plug in

n = 1

\frac{3}{2 7}

For

arcsin (x) + arcsin (2 x) = \frac{π}{3}

plug in

x = \frac{3}{2 7}

arcsin (\frac{3}{2 7}) + arcsin (2 \cdot \frac{3}{2 7}) = \frac{π}{3}

Refine

1.04719 \dots = 1.04719 \dots

\Rightarrow True

x = \frac{3}{2 7}

Popular Examples

2+cos(2x)=-5sin(x),0<= x<= 2pi

2 + cos (2 x) = - 5 sin (x), 0 \leq x \leq 2 π

tan(2x)= 4/3

tan (2 x) = \frac{4}{3}

sin(2x)=((9m-8))/2

sin (2 x) = \frac{( 9 m - 8 )}{2}

2=2+2cos(θ)

2 = 2 + 2 cos (θ)

cos(x)-sqrt(1-3cos^2(x))=0

cos (x) - 1 - 3 cos^{2} (x) = 0

Frequently Asked Questions (FAQ)

What is the general solution for arcsin(x)+arcsin(2x)= pi/3 ?
The general solution for arcsin(x)+arcsin(2x)= pi/3 is x=(sqrt(3))/(2sqrt(7))