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Popular Trigonometry >

tan(x)+cot(x)=6,sin^6(x)+cos^6(x)

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Solution

tan(x)+cot(x)=6,sin6(x)+cos6(x)

Solution

NoSolutionforx∈R
Solution steps
tan(x)+cot(x)=6,sin6(x)+cos6(x)
Subtract 6 from both sidestan(x)+cot(x)−6=0
Rewrite using trig identities
−6+cot(x)+tan(x)
Use the basic trigonometric identity: tan(x)=cot(x)1​=−6+cot(x)+cot(x)1​
−6+cot(x)+cot(x)1​=0
Solve by substitution
−6+cot(x)+cot(x)1​=0
Let: cot(x)=u−6+u+u1​=0
−6+u+u1​=0:u=3+22​,u=3−22​
−6+u+u1​=0
Multiply both sides by u
−6+u+u1​=0
Multiply both sides by u−6u+uu+u1​u=0⋅u
Simplify
−6u+uu+u1​u=0⋅u
Simplify uu:u2
uu
Apply exponent rule: ab⋅ac=ab+cuu=u1+1=u1+1
Add the numbers: 1+1=2=u2
Simplify u1​u:1
u1​u
Multiply fractions: a⋅cb​=ca⋅b​=u1⋅u​
Cancel the common factor: u=1
Simplify 0⋅u:0
0⋅u
Apply rule 0⋅a=0=0
−6u+u2+1=0
−6u+u2+1=0
−6u+u2+1=0
Solve −6u+u2+1=0:u=3+22​,u=3−22​
−6u+u2+1=0
Write in the standard form ax2+bx+c=0u2−6u+1=0
Solve with the quadratic formula
u2−6u+1=0
Quadratic Equation Formula:
For a=1,b=−6,c=1u1,2​=2⋅1−(−6)±(−6)2−4⋅1⋅1​​
u1,2​=2⋅1−(−6)±(−6)2−4⋅1⋅1​​
(−6)2−4⋅1⋅1​=42​
(−6)2−4⋅1⋅1​
Apply exponent rule: (−a)n=an,if n is even(−6)2=62=62−4⋅1⋅1​
Multiply the numbers: 4⋅1⋅1=4=62−4​
62=36=36−4​
Subtract the numbers: 36−4=32=32​
Prime factorization of 32:25
32
32divides by 232=16⋅2=2⋅16
16divides by 216=8⋅2=2⋅2⋅8
8divides by 28=4⋅2=2⋅2⋅2⋅4
4divides by 24=2⋅2=2⋅2⋅2⋅2⋅2
2 is a prime number, therefore no further factorization is possible=2⋅2⋅2⋅2⋅2
=25
=25​
Apply exponent rule: ab+c=ab⋅ac=24⋅2​
Apply radical rule: =2​24​
Apply radical rule: 24​=224​=22=222​
Refine=42​
u1,2​=2⋅1−(−6)±42​​
Separate the solutionsu1​=2⋅1−(−6)+42​​,u2​=2⋅1−(−6)−42​​
u=2⋅1−(−6)+42​​:3+22​
2⋅1−(−6)+42​​
Apply rule −(−a)=a=2⋅16+42​​
Multiply the numbers: 2⋅1=2=26+42​​
Factor 6+42​:2(3+22​)
6+42​
Rewrite as=2⋅3+2⋅22​
Factor out common term 2=2(3+22​)
=22(3+22​)​
Divide the numbers: 22​=1=3+22​
u=2⋅1−(−6)−42​​:3−22​
2⋅1−(−6)−42​​
Apply rule −(−a)=a=2⋅16−42​​
Multiply the numbers: 2⋅1=2=26−42​​
Factor 6−42​:2(3−22​)
6−42​
Rewrite as=2⋅3−2⋅22​
Factor out common term 2=2(3−22​)
=22(3−22​)​
Divide the numbers: 22​=1=3−22​
The solutions to the quadratic equation are:u=3+22​,u=3−22​
u=3+22​,u=3−22​
Verify Solutions
Find undefined (singularity) points:u=0
Take the denominator(s) of −6+u+u1​ and compare to zero
u=0
The following points are undefinedu=0
Combine undefined points with solutions:
u=3+22​,u=3−22​
Substitute back u=cot(x)cot(x)=3+22​,cot(x)=3−22​
cot(x)=3+22​,cot(x)=3−22​
cot(x)=3+22​,sin6(x)+cos6(x):No Solution
cot(x)=3+22​,sin6(x)+cos6(x)
Apply trig inverse properties
cot(x)=3+22​
General solutions for cot(x)=3+22​cot(x)=a⇒x=arccot(a)+πnx=arccot(3+22​)+πn
x=arccot(3+22​)+πn
Solutions for the range sin6(x)+cos6(x)NoSolution
cot(x)=3−22​,sin6(x)+cos6(x):No Solution
cot(x)=3−22​,sin6(x)+cos6(x)
Apply trig inverse properties
cot(x)=3−22​
General solutions for cot(x)=3−22​cot(x)=a⇒x=arccot(a)+πnx=arccot(3−22​)+πn
x=arccot(3−22​)+πn
Solutions for the range sin6(x)+cos6(x)NoSolution
Combine all the solutionsNoSolutionforx∈R

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Popular Examples

3cos(x)=3cos(2x)sin(3x)+sin(x)=2cos^2(x)tan(θ)= 5/92sin(x)+3cos(x)=0tan(x)+cot(x)=2sqrt(2)

Frequently Asked Questions (FAQ)

  • What is the general solution for tan(x)+cot(x)=6,sin^6(x)+cos^6(x) ?

    The general solution for tan(x)+cot(x)=6,sin^6(x)+cos^6(x) is No Solution for x\in\mathbb{R}
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