What is the axis x^2-4x-5 ?

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axis x^2-4x-5

axis

x^{2} - 4 x - 5

x = 2

Solution steps

y = x^{2} - 4 x - 5

Rewrite

y = x^{2} - 4 x - 5

in the standard form

4 \cdot \frac{1}{4} (y - (- 9)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 9), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y = 5 \cdot (x + 7 + 149) (x + 7 - 149)

30 x^{2} + 90 x + y + 64 = 0

y = (x - 7) (x - 9)

y = (3 x - 4) (4 x - 3) - 2 x

y = \frac{1}{2} x^{2} + x - 1