What is the axis y= 3/2 (x-4)^2+3 ?

The axis y= 3/2 (x-4)^2+3 is x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y= 3/2 (x-4)^2+3

axis

y = \frac{3}{2} (x - 4)^{2} + 3

x = 4

Solution steps

y = \frac{3}{2} (x - 4)^{2} + 3

Rewrite

y = \frac{3}{2} (x - 4)^{2} + 3

in the standard form:

4 \cdot \frac{1}{6} (y - 3) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 3), p = \frac{1}{6}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 4

y = k x^{2} + c

y = + x^{2} - 6

y = - (x + 1)^{2} + 1

y = \frac{4 x ^{3} - 7 x ^{2} - 11 x + 5}{4 x + 5}

x^{2} - 2 x - 4 y + 17 = 0