What is the axis y=(4x^3-7x^2-11x+5)/(4x+5) ?

The axis y=(4x^3-7x^2-11x+5)/(4x+5) is x= 3/2

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axis y=(4x^3-7x^2-11x+5)/(4x+5)

axis

y = \frac{4 x ^{3} - 7 x ^{2} - 11 x + 5}{4 x + 5}

x = \frac{3}{2}

Solution steps

y = \frac{4 x ^{3} - 7 x ^{2} - 11 x + 5}{4 x + 5}

Rewrite

y = \frac{4 x ^{3} - 7 x ^{2} - 11 x + 5}{4 x + 5}

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{5}{4})) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, - \frac{5}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{2}

x^{2} - 2 x - 4 y + 17 = 0

y = 2 x^{2} - 3 x

y = 3 x^{2} - 6 x - 24

y = 4 x^{2} + 8 x + 13

16 x^{2} - 72 x - 112 y = - 221

What is the axis y=(4x^3-7x^2-11x+5)/(4x+5) ?
The axis y=(4x^3-7x^2-11x+5)/(4x+5) is x= 3/2