What is the axis y=(3x-4)(4x-3)-2x ?

The axis y=(3x-4)(4x-3)-2x is x= 9/8

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axis y=(3x-4)(4x-3)-2x

axis

y = (3 x - 4) (4 x - 3) - 2 x

x = \frac{9}{8}

Solution steps

y = (3 x - 4) (4 x - 3) - 2 x

Rewrite

y = (3 x - 4) (4 x - 3) - 2 x

in the standard form

4 \cdot \frac{1}{48} (y - (- \frac{51}{16})) = (x - \frac{9}{8})^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{8}, - \frac{51}{16}), p = \frac{1}{48}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{9}{8}

y = \frac{1}{2} x^{2} + x - 1

y = x^{2} - 15 x

y = \frac{3}{2} (x - 4)^{2} + 3

y = k x^{2} + c

y = + x^{2} - 6