What is the axis y=x^2-15x ?

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axis y=x^2-15x

axis

y = x^{2} - 15 x

x = \frac{15}{2}

Solution steps

y = x^{2} - 15 x

Rewrite

y = x^{2} - 15 x

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{225}{4})) = (x - \frac{15}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{15}{2}, - \frac{225}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{15}{2}

y = \frac{3}{2} (x - 4)^{2} + 3

y = k x^{2} + c

y = + x^{2} - 6

y = - (x + 1)^{2} + 1

y = \frac{4 x ^{3} - 7 x ^{2} - 11 x + 5}{4 x + 5}