What is the axis y=0.09x^2+17x+350 ?

The axis y=0.09x^2+17x+350 is x=-94.44444…

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axis y=0.09x^2+17x+350

axis

y = 0.09 x^{2} + 17 x + 350

x = - 94.44444 \dots

Solution steps

y = 0.09 x^{2} + 17 x + 350

Rewrite

y = 0.09 x^{2} + 17 x + 350

in the standard form

4 \cdot 2.77777 \dots (y - (- 452.77777 \dots)) = (x - (- 94.44444 \dots))^{2}

Therefore parabola properties are:

(h, k) = (- 94.44444 \dots, - 452.77777 \dots), p = 2.77777 \dots

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 94.44444 \dots

y = 3 - 4 x^{2}

y = x^{2} - 4 x + 12

(x + 2)^{2} = - 6 (y - 1)

y = 4 x + 4 x - 2 + x^{2} - 3

y = - x^{2} - 4 x - 3