What is the axis y=-x^2-4x-3 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=-x^2-4x-3

axis

y = - x^{2} - 4 x - 3

x = - 2

Solution steps

y = - x^{2} - 4 x - 3

Rewrite

y = - x^{2} - 4 x - 3

in the standard form

4 (- \frac{1}{4}) (y - 1) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 1), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 2

y = - x^{2} + 3 x + 5

y = (x + 12) (x - 12)

y = 12 x^{2} - 17 x + 6

x = 4 y^{2} + 8 y - 3

y^{2} = 9 x