What is the axis y=3-4x^2 ?

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axis y=3-4x^2

axis

y = 3 - 4 x^{2}

x = 0

Solution steps

y = 3 - 4 x^{2}

Rewrite

y = 3 - 4 x^{2}

in the standard form:

4 (- \frac{1}{16}) (y - 3) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 3), p = - \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = x^{2} - 4 x + 12

(x + 2)^{2} = - 6 (y - 1)

y = 4 x + 4 x - 2 + x^{2} - 3

y = - x^{2} - 4 x - 3

y = - x^{2} + 3 x + 5