What is the axis y=4x+4x-2+x^2-3 ?

The axis y=4x+4x-2+x^2-3 is x=-4

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axis y=4x+4x-2+x^2-3

axis

y = 4 x + 4 x - 2 + x^{2} - 3

x = - 4

Solution steps

y = 4 x + 4 x - 2 + x^{2} - 3

Rewrite

y = 4 x + 4 x - 2 + x^{2} - 3

in the standard form

4 \cdot \frac{1}{4} (y - (- 21)) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, - 21), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 4

y = - x^{2} - 4 x - 3

y = - x^{2} + 3 x + 5

y = (x + 12) (x - 12)

y = 12 x^{2} - 17 x + 6

x = 4 y^{2} + 8 y - 3