What is the axis y=(3x+4)^2 ?

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axis y=(3x+4)^2

axis

y = (3 x + 4)^{2}

x = - \frac{4}{3}

Solution steps

y = (3 x + 4)^{2}

Rewrite

y = (3 x + 4)^{2}

in the standard form:

4 \cdot \frac{1}{36} (y - 0) = (x - (- \frac{4}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{4}{3}, 0), p = \frac{1}{36}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{4}{3}

y = x^{2} + 2

y^{2} = - \frac{4}{5} (x - 2)

y = 0.09 x^{2} + 17 x + 350

y = 3 - 4 x^{2}

y = x^{2} - 4 x + 12