What is the axis y=x^2+2 ?

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axis y=x^2+2

axis

y = x^{2} + 2

x = 0

Solution steps

y = x^{2} + 2

Rewrite

y = x^{2} + 2

in the standard form:

4 \cdot \frac{1}{4} (y - 2) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 2), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y^{2} = - \frac{4}{5} (x - 2)

y = 0.09 x^{2} + 17 x + 350

y = 3 - 4 x^{2}

y = x^{2} - 4 x + 12

(x + 2)^{2} = - 6 (y - 1)