What is the axis y=5x^2-4x+3 ?

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axis y=5x^2-4x+3

axis

y = 5 x^{2} - 4 x + 3

x = \frac{2}{5}

Solution steps

y = 5 x^{2} - 4 x + 3

Rewrite

y = 5 x^{2} - 4 x + 3

in the standard form

4 \cdot \frac{1}{20} (y - \frac{11}{5}) = (x - \frac{2}{5})^{2}

Therefore parabola properties are:

(h, k) = (\frac{2}{5}, \frac{11}{5}), p = \frac{1}{20}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{2}{5}

y = x^{2} - 4 x + 4

y = (3 x + 4)^{2}

y = x^{2} + 2

y^{2} = - \frac{4}{5} (x - 2)

y = 0.09 x^{2} + 17 x + 350