What is the axis y=6x^2+6x-36 ?

The axis y=6x^2+6x-36 is x=-1/2

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axis y=6x^2+6x-36

axis

y = 6 x^{2} + 6 x - 36

x = - \frac{1}{2}

Solution steps

y = 6 x^{2} + 6 x - 36

Rewrite

y = 6 x^{2} + 6 x - 36

in the standard form

4 \cdot \frac{1}{24} (y - (- \frac{75}{2})) = (x - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, - \frac{75}{2}), p = \frac{1}{24}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{1}{2}

y = 5 x^{2} - 4 x + 3

y = x^{2} - 4 x + 4

y = (3 x + 4)^{2}

y = x^{2} + 2

y^{2} = - \frac{4}{5} (x - 2)