What is the foci ((x-4)^2}{36}-\frac{(y-2)^2)/9 =1 ?

The foci ((x-4)^2}{36}-\frac{(y-2)^2)/9 =1 is (4+3sqrt(5),2),(4-3sqrt(5),2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

foci ((x-4)^2}{36}-\frac{(y-2)^2)/9 =1

foci

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1

(4 + 35, 2), (4 - 35, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (4, 2), a = 6, b = 3

(4 + c, 2), (4 - c, 2)

Compute

c :

c = 6^{2} + 3^{2} : 35

(4 + 35, 2), (4 - 35, 2)

What is the foci ((x-4)^2}{36}-\frac{(y-2)^2)/9 =1 ?
The foci ((x-4)^2}{36}-\frac{(y-2)^2)/9 =1 is (4+3sqrt(5),2),(4-3sqrt(5),2)