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Popular >

vertices x^2=4y-2y^2

Solution

vertices

x^{2} = 4 y - 2 y^{2}

Solution

(2, 1), (- 2, 1)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

x^{2} = 4 y - 2 y^{2} :

Ellipse with center

(h, k) = (0, 1), a = 2, b = 1

(0 + 2, 1), (0 - 2, 1)

Refine

(2, 1), (- 2, 1)

Popular Examples

x = (y - 5)^{2}

(x-2)^2=12(y+3)

(x - 2)^{2} = 12 (y + 3)

(y-2)^2=12(x+1)

(y - 2)^{2} = 12 (x + 1)

vertices f(x)=x^2+2x vertices

f (x) = x^{2} + 2 x

vertices (x^2)/(64)+(y^2)/(16)=1 vertices

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

Frequently Asked Questions (FAQ)

What is the vertices x^2=4y-2y^2 ?
The vertices x^2=4y-2y^2 is (sqrt(2),1),(-sqrt(2),1)