What is (y-2)^2=12(x+1) ?

The solution to (y-2)^2=12(x+1) is Parabola with (h,k)=(-1,2),p=3

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(y-2)^2=12(x+1)

(y - 2)^{2} = 12 (x + 1)

(h, k) = (- 1, 2), p = 3

Solution steps

(y - 2)^{2} = 12 (x + 1)

Rewrite

(y - 2)^{2} = 12 (x + 1)

in the standard form:

4 \cdot 3 (x - (- 1)) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (- 1, 2), p = 3

f (x) = x^{2} + 2 x

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

2 x^{2} + y^{2} = 2

y^{2} + 6 y + 9 = x + 8

x^{2} + 4 x - 4 y = 0

What is (y-2)^2=12(x+1) ?
The solution to (y-2)^2=12(x+1) is Parabola with (h,k)=(-1,2),p=3