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Popular >

foci x^2+4x-4y=0

Solution

foci

x^{2} + 4 x - 4 y = 0

Solution

(- 2, 0)

Solution steps

Rewrite

x^{2} + 4 x - 4 y = 0

in the standard form

4 \cdot 1 \cdot (y - (- 1)) = (x - (- 2))^{2}

(h, k) = (- 2, - 1), p = 1

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 2, - 1)

along the y-axis

(- 2, - 1 + p)

= (- 2, - 1 + 1)

Refine

(- 2, 0)

Popular Examples

x^2+y^2-4x+8y-5=0

x^{2} + y^{2} - 4 x + 8 y - 5 = 0

directrix x=2y^2 directrix

x = 2 y^{2}

foci 0=-400/9 x^2+16y^2+400 foci

0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400

5 x^{2} + 7 y = 3

center 41x^2+16y^2+246x-192y+289=0 center

41 x^{2} + 16 y^{2} + 246 x - 192 y + 289 = 0

Frequently Asked Questions (FAQ)

What is the foci x^2+4x-4y=0 ?
The foci x^2+4x-4y=0 is (-2,0)