What is (x-2)^2=12(y+3) ?

The solution to (x-2)^2=12(y+3) is Parabola with (h,k)=(2,-3),p=3

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(x-2)^2=12(y+3)

(x - 2)^{2} = 12 (y + 3)

(h, k) = (2, - 3), p = 3

Solution steps

(x - 2)^{2} = 12 (y + 3)

Rewrite

(x - 2)^{2} = 12 (y + 3)

in the standard form:

4 \cdot 3 (y - (- 3)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 3), p = 3

(y - 2)^{2} = 12 (x + 1)

f (x) = x^{2} + 2 x

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

2 x^{2} + y^{2} = 2

y^{2} + 6 y + 9 = x + 8

What is (x-2)^2=12(y+3) ?
The solution to (x-2)^2=12(y+3) is Parabola with (h,k)=(2,-3),p=3