What is x^2+y^2+10x+12y+25=0 ?

The solution to x^2+y^2+10x+12y+25=0 is Circle with (a,b)=(-5,-6),r=6

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x^2+y^2+10x+12y+25=0

x^{2} + y^{2} + 10 x + 12 y + 25 = 0

(a, b) = (- 5, - 6), r = 6

Solution steps

x^{2} + y^{2} + 10 x + 12 y + 25 = 0

Rewrite

x^{2} + y^{2} + 10 x + 12 y + 25 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 6))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 6), r = 6

x^{2} = 16 y

y^{2} = - 10 x

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

f (x) = x^{2} - 4

- x^{2} + 9 y^{2} + 4 x + 54 y + 68 = 0

What is x^2+y^2+10x+12y+25=0 ?
The solution to x^2+y^2+10x+12y+25=0 is Circle with (a,b)=(-5,-6),r=6