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Beliebt Geometry >

leitkurve y^2=-10x

Lösung

leitkurve

y^{2} = - 10 x

Lösung

x = \frac{5}{2}

Schritte zur Lösung

Rewrite

y^{2} = - 10 x

in the standard form:

4 (- \frac{5}{2}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{5}{2}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{5}{2})

Fasse zusammen

x = \frac{5}{2}

Graph

Beliebte Beispiele

exzentrizität (x^2)/(25)+(y^2)/(25)=1

ecce n t r i c i t y \frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

scheitelpunkte f(x)=x^2-4

v er t i ces f (x) = x^{2} - 4

-x^2+9y^2+4x+54y+68=0

- x^{2} + 9 y^{2} + 4 x + 54 y + 68 = 0

leitkurve x=-1/8 y^2

d i rec t r i x x = - \frac{1}{8} y^{2}

asymptoten 4x^2-y^2=16

a sy m pt o t es 4 x^{2} - y^{2} = 16