What is the eccentricity (x^2)/(25)+(y^2)/(25)=1 ?

The eccentricity (x^2)/(25)+(y^2)/(25)=1 is 0

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eccentricity (x^2)/(25)+(y^2)/(25)=1

eccentricity

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

0

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 5

= \frac{5 ^{2} - 5 ^{2}}{5}

\frac{5 ^{2} - 5 ^{2}}{5} = 0

= 0

f (x) = x^{2} - 4

- x^{2} + 9 y^{2} + 4 x + 54 y + 68 = 0

x = - \frac{1}{8} y^{2}

4 x^{2} - y^{2} = 16

x^{2} + y^{2} - 4 x - 4 y = 0

What is the eccentricity (x^2)/(25)+(y^2)/(25)=1 ?
The eccentricity (x^2)/(25)+(y^2)/(25)=1 is 0