What is the foci (x^2}{25}-\frac{y^2)/9 =1 ?

The foci (x^2}{25}-\frac{y^2)/9 =1 is (sqrt(34),0),(-sqrt(34),0)

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foci (x^2}{25}-\frac{y^2)/9 =1

foci

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

(34, 0), (- 34, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} + 3^{2} : 34

(0 + 34, 0), (0 - 34, 0)

Refine

(34, 0), (- 34, 0)

x = y^{2} - 2

y^{2} - 12 y + 4 x + 4 = 0

x = y^{2} - 4 y

y^{2} = - 9 x

9 x^{2} - 16 y^{2} = 144

What is the foci (x^2}{25}-\frac{y^2)/9 =1 ?
The foci (x^2}{25}-\frac{y^2)/9 =1 is (sqrt(34),0),(-sqrt(34),0)