x=y^2-4y

Solution

x = y^{2} - 4 y

(h, k) = (- 4, 2), p = \frac{1}{4}

Solution steps

x = y^{2} - 4 y

Rewrite

x = y^{2} - 4 y

in the standard form

4 \cdot \frac{1}{4} (x - (- 4)) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 2), p = \frac{1}{4}

y^{2} = - 9 x

9 x^{2} - 16 y^{2} = 144

f (x) = 3 x^{2} - 12 x + 4

16 x^{2} + 9 y^{2} = 144

f (x) = x^{2} - 3 x + 2

What is x=y^2-4y ?
The solution to x=y^2-4y is Parabola with (h,k)=(-4,2),p= 1/4