What is the vertices 9x^2-16y^2=144 ?

The vertices 9x^2-16y^2=144 is (4,0),(-4,0)

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vertices 9x^2-16y^2=144

vertices

9 x^{2} - 16 y^{2} = 144

(4, 0), (- 4, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

9 x^{2} - 16 y^{2} = 144 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 4, b = 3

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

f (x) = 3 x^{2} - 12 x + 4

16 x^{2} + 9 y^{2} = 144

f (x) = x^{2} - 3 x + 2

f (x) = x^{2} + 3 x - 4

x^{2} + 4 y^{2} = 16

What is the vertices 9x^2-16y^2=144 ?
The vertices 9x^2-16y^2=144 is (4,0),(-4,0)