What is y^2-12y+4x+4=0 ?

The solution to y^2-12y+4x+4=0 is Parabola with (h,k)=(8,6),p=-1

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y^2-12y+4x+4=0

y^{2} - 12 y + 4 x + 4 = 0

(h, k) = (8, 6), p = - 1

Solution steps

y^{2} - 12 y + 4 x + 4 = 0

Rewrite

y^{2} - 12 y + 4 x + 4 = 0

in the standard form

4 (- 1) (x - 8) = (y - 6)^{2}

Therefore parabola properties are:

(h, k) = (8, 6), p = - 1

x = y^{2} - 4 y

y^{2} = - 9 x

9 x^{2} - 16 y^{2} = 144

f (x) = 3 x^{2} - 12 x + 4

16 x^{2} + 9 y^{2} = 144

What is y^2-12y+4x+4=0 ?
The solution to y^2-12y+4x+4=0 is Parabola with (h,k)=(8,6),p=-1