Solution
Solution
Solution steps
Rewrite in the standard form:
Therefore parabola properties are:
Popular Examples
vertices f(x)=-x^2+4vertices x^2+y^2=93x^2-8y^2+12x+16y+20=0vertices f(x)=-3x^2+6x-1vertices ((y+2)^2}{16}-\frac{(x-3)^2)/9 =1
Frequently Asked Questions (FAQ)
What is x^2+y=4 ?
The solution to x^2+y=4 is Parabola with (h,k)=(0,4),p=-1/4