x^2+y^2=9

Solution

x^{2} + y^{2} = 9

(a, b) = (0, 0), r = 3

Solution steps

x^{2} + y^{2} = 9

Rewrite

x^{2} + y^{2} = 9

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 3

3 x^{2} - 8 y^{2} + 12 x + 16 y + 20 = 0

f (x) = - 3 x^{2} + 6 x - 1

\frac{( y + 2 ) ^{2}}{16} - \frac{( x - 3 ) ^{2}}{9} = 1

f (x) = x^{2} - 2 x - 8

x^{2} - y = 4