What is the directrix x=4y^2 ?

The directrix x=4y^2 is x=-1/16

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directrix x=4y^2

directrix

x = 4 y^{2}

x = - \frac{1}{16}

Solution steps

Rewrite

x = 4 y^{2}

in the standard form:

4 \cdot \frac{1}{16} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{16}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - \frac{1}{16}

Refine

x = - \frac{1}{16}

9 x^{2} + 4 y^{2} = 36

f (x) = x^{2} - x - 6

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0

y^{2} - 4 y + 4 x = - 16

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1