What is y^2-4y+4x=-16 ?

The solution to y^2-4y+4x=-16 is Parabola with (h,k)=(-3,2),p=-1

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y^2-4y+4x=-16

y^{2} - 4 y + 4 x = - 16

(h, k) = (- 3, 2), p = - 1

Solution steps

y^{2} - 4 y + 4 x = - 16

Rewrite

y^{2} - 4 y + 4 x = - 16

in the standard form

4 (- 1) (x - (- 3)) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (- 3, 2), p = - 1

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1

f (x) = x^{2} + 4

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

\frac{x ^{2}}{169} + \frac{y ^{2}}{25} = 1

2 x - y^{2} = 4

What is y^2-4y+4x=-16 ?
The solution to y^2-4y+4x=-16 is Parabola with (h,k)=(-3,2),p=-1