What is the center 9x^2+4y^2=36 ?

The center 9x^2+4y^2=36 is (0,0)

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center 9x^2+4y^2=36

center

9 x^{2} + 4 y^{2} = 36

(0, 0)

Solution steps

9 x^{2} + 4 y^{2} = 36

Rewrite

9 x^{2} + 4 y^{2} = 36

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 2

And the center is:

(0, 0)

f (x) = x^{2} - x - 6

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0

y^{2} - 4 y + 4 x = - 16

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1

f (x) = x^{2} + 4