What is 3.5(x+2.2)^2+3.5(y-11.1)^2-21=0 ?

The solution to 3.5(x+2.2)^2+3.5(y-11.1)^2-21=0 is Circle with (a,b)=(-2.2,11.1),r=sqrt(6)

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3.5(x+2.2)^2+3.5(y-11.1)^2-21=0

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0

(a, b) = (- 2.2, 11.1), r = 6

Solution steps

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0

Rewrite

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0

in the form of the standard circle equation

(x - (- 2.2))^{2} + (y - 11.1)^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (- 2.2, 11.1), r = 6

y^{2} - 4 y + 4 x = - 16

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1

f (x) = x^{2} + 4

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

\frac{x ^{2}}{169} + \frac{y ^{2}}{25} = 1

What is 3.5(x+2.2)^2+3.5(y-11.1)^2-21=0 ?
The solution to 3.5(x+2.2)^2+3.5(y-11.1)^2-21=0 is Circle with (a,b)=(-2.2,11.1),r=sqrt(6)