What is (x^2)/4+(y^2)/(25)=1 ?

The solution to (x^2)/4+(y^2)/(25)=1 is Ellipse with (h,k)=(0,0),a=2,b=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2)/4+(y^2)/(25)=1

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

(h, k) = (0, 0), a = 2, b = 5

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 2

f (x) = x^{2} + 4 x + 4

x = 4 y^{2}

9 x^{2} + 4 y^{2} = 36

f (x) = x^{2} - x - 6

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0

What is (x^2)/4+(y^2)/(25)=1 ?
The solution to (x^2)/4+(y^2)/(25)=1 is Ellipse with (h,k)=(0,0),a=2,b=5