What is 32=(x-3)^2+(y+1)^2 ?

The solution to 32=(x-3)^2+(y+1)^2 is Circle with (a,b)=(3,-1),r=4sqrt(2)

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32=(x-3)^2+(y+1)^2

32 = (x - 3)^{2} + (y + 1)^{2}

(a, b) = (3, - 1), r = 42

Solution steps

32 = (x - 3)^{2} + (y + 1)^{2}

Rewrite

32 = (x - 3)^{2} + (y + 1)^{2}

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 1))^{2} = (42)^{2}

Therefore the circle properties are:

(a, b) = (3, - 1), r = 42

What is 32=(x-3)^2+(y+1)^2 ?
The solution to 32=(x-3)^2+(y+1)^2 is Circle with (a,b)=(3,-1),r=4sqrt(2)